1) Refer back to Lesson 2, Part A. Assume that the average shoulder width of the people in the line was 1.325 feet. How long would the line be if it contained 10 million people? Express your answer in feet.​

Answers

Answer 1
Answer:

Answer:

13,250,000 feet or 13.25 million feet

Step-by-step explanation:

Each person in the line has a shoulder width of 1.325 feet.

For each person, there is a width of 1.325 ft. There are 10 million people.

Since:

10 million = 10,000,000

The total length must be:

1.325 * 10,000,000

1.325 * 10,000,000 = 13,250,000

Answer: 13,250,000 feet or 13.25 million feet

Answer 2
Answer:

Final answer:

By simply multiplying the average shoulder width of the people (1.325 feet) by the total number of people in the line (10 million), the total length of the line would be 13,250,000 feet.

Explanation:

This problem can be solved by using simple multiplication. Given that the average shoulder width of the people in the line is 1.325 feet, we simply need to multiply this by the total number of people in the line, which is 10 million in this case.

So, 1.325 feet * 10,000,000 = 13,250,000 feet.

Therefore, if there were 10 million people in line, and the average shoulder width of each person is 1.325 feet, the total length of the line would be 13,250,000 feet.

Learn more about Multiplication here:

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An office building loses a third of its heat between sundown and midnight and an additional half of the original amount of heat between midnight and 4 AM. If five-eighths of the remaining heat is lost between 4 AM and 5 AM, what proportion of the total heat loss occurs between 5 AM and sunrise?

Answers

Answer:

(1)/(16)

Step-by-step explanation:

Proportion of Heat Loss Between sundown and midnight=(1)/(3)

Proportion of Heat Loss between midnight and 4 AM  =(1)/(2)

Proportion of Total Heat Already Lost =(1)/(3)+(1)/(2) =(5)/(6)

Proportion of Remaining Heat =1-(5)/(6)=(1)/(6)

Between 4 AM and 5 AM, five-eighths of the remaining heat is lost.

Proportion of Heat Loss between 4 AM and 5 AM= (5)/(8)$ X (1)/(6) = (5)/(48)

Therefore, Proportion of Remaining Heat Left =(1)/(6)- (5)/(48)=(1)/(16)

We therefore say that:

(1)/(16)$ of the total heat loss occurs between 5 AM and sunrise.

|)) Which sign makes the statement true?
83.95% ? 83.95%
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Submit

Answers

Answer:  =

Step-by-step explanation:

83.95% is equal to 83.95% (look at it)

Answer:

=

Step-by-step explanation:

umm 83.95 = 83.95?

An aptitude test has a mean score of 80 and a standard deviation of 5. The population of scores is normally distributed. What raw score corresponds to the 70th percentile?

Answers

Answer:

82.62

Step-by-step explanation:

Mean score (μ) = 80

Standard deviation (σ) = 5

The 70th percentile of a normal distribution has an equivalent z-score of roughly 0.525.

For any given score, X, the z-score can be determined by:

z=(X-\mu)/(\sigma)

For z = 0.525:

0.525=(X-80)/(5)\n X=82.62

A raw score of approximately 82.62 corresponds to the 70th percentile.

Answer: the raw score that corresponds to the 70th percentile is 82.625

Step-by-step explanation:

Since the population of scores in the aptitude test is normally distributed., we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = aptitude test scores.

µ = mean score

σ = standard deviation

From the information given,

µ = 80

σ = 5

We want to find the raw score that corresponds to the 70th percentile.

70th percentile = 70/100 = 0.7

Looking at the normal distribution table, the z score corresponding to 0.7 is 0.525.

Therefore,

0.525 = (x - 80)/5

5 × 0.525 = x - 80

2.625 = x - 80

x = 2.625 + 80

x = 82.625

WXYZ is a parallelogram. Name an angle congruent to ∠WZY.

Answers

Answer:

Angle congruent to ∠WZY is ∠WXY

2x+3y=-11, and x=2y+12 solve in substition equations

Answers

The answer would be (2,-5)
Because you know the equation for what x is, you can substitute (2y+12) for x. Your new equation would look like this;

2(2y+12)+3y=-11

Distribute the 2 into 2y+12

4y+24+3y=-11

Add 4y and 3y

7y+24=-11

Subtract 24 from both sides

7y=-35

y=-5


Now, substitute -5 in for y in the 2nd equation.

x= 2(-5)+12
x=-10+12
x=2


x=-5
y=2

Hope this helped! You can reach out to me if you have any more questions!

The height of a cylinder is decreasing at a constant rate of 1 centimeters per minute, and the volume is decreasing at a rate of 2341 cubic centimeters per minute. At the instant when the height of the cylinder is 1010 centimeters and the volume is 577 cubic centimeters, what is the rate of change of the radius? The volume of a cylinder can be found with the equation V=pi r^2 h. Round your answer to three decimal places.

Answers

Let's organize our given information.

(dh)/(dt)=-1

(dV)/(dt)=-2341

(dr)/(dt)=?, h=1010, V=577

V=\pi r^2h

What I'd like to do is solve for r first, it'll help later.

577=\pi r^2(1010)

r=\sqrt{(577)/(1010\pi)}

r=0.426

Now, we can differentiate our formula for the volume of a cylinder to find the rate of change of the radius.

V=\pi r^2h

Use the product rule of differentiation.

(dV)/(dt)=2\pi rh(dr)/(dt)+\pi r^2(dh)/(dt)

Plug in the information we are given.

-2341=2\pi (0.426)(1010)(dr)/(dt)+\pi (0.426)^2(-1)

Solve for (dr)/(dt).

-2341=860.52\pi(dr)/(dt)+(0.426)^2\pi

-2341.57=860.52\pi(dr)/(dt)

(dr)/(dt)=-0.866

The rate of change of the radius is -0.866 centimeters per minute.

Hope this helps!