What is 0.55 as a fraction in it's simplest form?

Answers

Answer 1

Answer: $0.55=(55)/(100)=(55:5)/(100:5)=(11)/(20)$

Answer 2

Answer: 0.55 IN A FRACTION IS 55/100 =11/20 (SIMPLEST FORM)

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Let x^2−12x=61 . What values make an equivalent number sentence after completing the square? Enter your answers in the boxes. HELP PLEASE

Please help! The selected one is wrong

Answers

Answer:

option b

Step-by-step explanation:

(fog)x = f(g(x))

Option b

= f(x - 5)

= [2 (x-5) ]² + 1

= [2x - 10]² + 1 ≠ h(x)

Demonstrates the commutative property across multiplication for 2 × 10 × 7

Answers

Commutative means that you can mix up the numbers, but still have the right answer.

2 x 10 x 7 =
2 x 7 x 10 =
10 x 2 x 7 =
10 x 7 x 2 =
7 x 2 x 10 =
7 x 10 x 2

Hope this helps :)

Choose the equivalent system of linear equations that will produce the same solution as the one given below.6x + 2y = −6
3x − 4y = −18

12x + 4y = −12
15x = −30
8x + 4y = −4
14x = −10
6x − 8y = −36
−6y = −42
6x − y = −15
3y = 9

Answers

The given system of equation:
$6x+2y=-6 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |* 2 \n3x-4y=-18 \n \n12x+4y=-12 \n\underline{3x-4y=-18 \ \ } \n15x=-30 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ 15 \nx=-2 \n \n3x-4y=-18 \n3 * (-2)-4y=-18 \n-6-4y=-18 \ \ \ \ \ \ \ \ \ \ \ \ |+6 \n-4y=-12 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ (-4) \ny=3 \n \n(x,y)=(-2,3)$

Answer options:
1.
$12x+4y=-12 \n15x=-30 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ 15 \n \n12x+4y=-12 \nx=-2 \n \n12 * (-2)+4y=-12 \n-24+4y=-12 \ \ \ \ \ \ \ \ \ \ |+24 \n4y=12 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ 4 \ny=3 \n \n(x,y)=(-2,3) \n\hbox{the same solution}$

2.
$8x+4y=-4 \n14x=-10 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ 14 \n \n8x+4y=-4 \nx=-(10)/(14)=-(5)/(7) \n \nx=-(5)/(7) \not= -2 \n\hbox{not the same solution}$

3.
$6x-8y=-36 \n-6y=-42 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ (-6) \n \n6x-8y=-36 \ny=7 \n \ny=7 \not= 3 \n\hbox{not the same solution}$

4.
$6x-y=-15 \n3y=9 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ 3 \n \n6x-y=-15 \ny=3 \n \n6x-3=-15 \ \ \ \ \ \ \ \ \ |+3 \n6x=-12 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |/ 6 \nx=-2 \n \n(x,y)=(-2,3) \n\hbox{the same solution}$

The equivalent systems of equations are 1 and 4:
12x+4y=-12
15x=-30
and
6x-y=-15
3y=9

Answer:12x+4y=-12

15x=-30

Step-by-step explanation:

just took the test and had to use the answer below to get it right but they got to answers :// thats dumb but theres the answer start forward

YOUR WELCOME

WILL GIVE BRAINLIESTHannah and Han are each trying to solve the equation x² – 8x + 26 = 0. They know that
x = -1 are i& - i, but they are not sure how to use this information to solve for x in their
equation.
Part 1- Here is Hannah's work:
x? - 8x + 26 = 0
X? – 8x = -26
Show Hannah how
to finish her work using completing the square and complex numbers.
Part 2- Han decides to solve the equation using the quadratic
formula. Here is the beginning of his
work
-b+V62-4ac
-(-8)+7-8)2–401|(26)
Finish using the quadratic formula. Simplify the final answer as much as possible.

Answers

The solutions are:-

$x=4+√(10i)\n\nx=4-√(10i)$

What is the equation?

The definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.

Here given equation is

$x^2- 8x + 26 = 0\n\nx^2-8x=-26\n\n(x-4)^2=-10\n\n$

$(x-4)=$ ± $√(-10)$

$x=√(10)i+4\n\nx=-√(10)i+4$

So,

$x=(-b+-√(b^2-4ac))/(2a)\n\nx=(8+-√((-8)^2-4(1)(26)))/(2(1))\n\nx=(8+-√((-8)^2-4(1)(26)))/(2(1))\n\nx=(8+-√(64-104))/(2)\n\nx=(8+-2√(10i))/(2)\n\nx=(2(4+-√(10i)))/(2)\n\nx=4+√(10i)\n\nx=4-√(10i)$

Hence, the solutions are:-

$x=4+√(10i)\n\nx=4-√(10i)$

To know more about the equation

brainly.com/question/12788590

#SPJ2

Part one:

$x^2-8x=-26$

Rewrite in the form $(x+a)^(2) =b$

$\left(x-4\right)^2=-10$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=√(a),\:-√(a)$

Solve $x-4=√(-10) : x=√(10) i+4$

Solve $x-4=√(-10) : x=-√(10) i+4$

$x=√(10)i+4,\:x=-√(10)i+4$

Part two:

$x=(-\left(-8\right)\pm √(\left(-8\right)^2-4\cdot \:1\cdot \:26))/(2\cdot \:1)$

Simplify $√(\left(-8\right)^2-4\cdot \:1\cdot \:26)}: 2√(10) i$

$=(-\left(-8\right)\pm \:2√(10)i)/(2\cdot \:1)$

Separate solutions

$x_1=(-\left(-8\right)+2√(10)i)/(2\cdot \:1),\:x_2=(-\left(-8\right)-2√(10)i)/(2\cdot \:1)$

$(-(-8)+2√(10)i )/(2*1) :4+√(10)i$

$(-(-8)+2√(10)i )/(2*1) :4-√(10)i$

$x=4+√(10)i,\:x=4-√(10)i$

Five times a number is added to two times its square. if the result is 168, find the number

Answers

5x+(2x)^2= 168 now solve this

Two black chips and three red chips are put into a bag. Two points are awarded for each black chip drawn, and one point is lost for each red chip drawn. What is the expected value for each round if there are two draws per round and the chips are replaced after each draw?

Answers

The answer is 0.4.

The values are:
- for the black chip : x₁ = 2
- for the red chip: x₂ = -1

Let's first calculate the possibilities of each chip. There are in total 5 chips (two black chips and three red chips) in the bag
- the possibility to draw the black chip is 2 out of 5: P₁ = 2/5
- the possibility to draw the red chip is 3 out of 5: P₂ = 3/5

In this example we have 4 different events:
1. Drawing of two black chips: P₃ = P₁ · P₁ = 2/5 · 2/5 = 4/25
2. Drawing of one black chip and then one red chip: P₄ = P₁ · P₂ = 2/5 · 3/5 = 6/25
3. Drawing of one red chip and then one black chip: P₅ = P₂ · P₁ = 3/5 · 2/5 = 6/25
5. Drawing of two black chips: P₆ = P₂ · P₂ = 3/5 · 3/5 = 9/25

Therefore, the expected value for each round if there are two draws per round and the chips are replaced after each draw is 0.4:
P = (x₁ + x₁) · P₃ + (x₁ + x₂) · P₄ + (x₁ + x₂) · P₅ + (x₂ + x₂) · P₆
P = (2+2) · 4/25 + (2-1) · 6/25 + (2-1) · 6/25 + (-1 + -1) · 9/25
P = 4 · 4/25 + 1 · 6/25 + 1 · 6/25 + -2 · 9/25
P = 16/25 + 6/25 + 6/25 - 18/25
P = 28/25 - 18/25
P = 10/25 = 0.4

Answer:

0.4 is correct

Step-by-step explanation:

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3/9 in simplest form