What’s the perimeter and area
What’s the perimeter and area - 1

Answers

Answer 1
Answer:

Answer:

perimeter= 2(a + b) mi

area= a×b mi squares

Step-by-step explanation:

Answer 2
Answer:

Answers:

24 mm², 26.5 mm

Step-by-step explanation:

Area of the triangle:

A=(b*h)/(2)\n\nA=(12*4)/(2)\n\n A=(48)/(2)\n\n \boxed{A=24}

Perimeter of the triangle:

P=a+b+c \text{ (The side measurements of the triangle.)}\n\nP=6+12+8.5\n\n\boxed{P=26.5}

Hope this helps.


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Sumita is following this recipe to make flapjacks.Sumita uses 20 g of sugar.
How many flapjacks is Sumita making?
Recipe: Makes 14 flapjacks
220 g margarine
140 g sugar
140 ml syrup
250 g oats
30 g sultanas

Answers

20flapjacks

Step-by-step explanation:

so this is the answer

Answer:

20 flapjacks

Step-by-step explanation:

Select the algebraic definition for the piecewise function graph.A. 2
B. 4
C. -3 is equal to x <-1
D. -1 is equal to x <1
E. 0
F. 1 is equal to x<3
G. -2 is equal to x<5
H. -3 is equal to x<3
I. 3

Answers

The piece-wise function is defined by:

f(x) = 1, -3 \leq x < -1

f(x) = 2, -1 \leq x < 1

f(x) = 3,  1 \leq x < 3

A piece-wise function is a function that has different definitions, based on the input.

In this graph:

  • When x is between -3(inclusive, closed circle) and -1(exclusive, open circle), the value is 1, thus, the first definition is:

f(x) = 1, -3 \leq x < -1

  • When x is between -1(inclusive) and 1(exclusive), the value is 2, thus, the second definition is:

f(x) = 2, -1 \leq x < 1

  • When x is between 1(inclusive) and 3(exclusive), the value is 3, thus, the third definition is:

f(x) = 3, 1 \leq x < 3

A similar problem is given at brainly.com/question/13205719

Final answer:

A piecewise function is defined by multiple sub-functions, each applying to a certain interval of the main function's domain. An example might be ' -3 is equal to x <-1', representing a portion of the function where any x-value less than -1 outputs -3.

Explanation:

Without the piecewise function graph, it's difficult to identify the correct algebraic definition. However, a piecewise function is a function which is defined by multiple sub functions. Each sub function applies to a certain interval of the main function's domain, which is why we see conditions like 'x < -1' following the function.

For instance, if we look at option C ' -3 is equal to x <-1', it suggests there is a piece of the function where any x-value less than -1 will output -3. It is important to note that these piecewise functions are visualized on a graph, often appearing as lines or curves that start or stop at certain points.

Learn more about Piecewise Functions here:

brainly.com/question/32038875

#SPJ11

What is the percentage of 199.50 out of 286?

Answers

286 = 100 %
199.5 = x

In order to find x we need to cross multiply 286*x=199.5*100
286x=19950     / 286
x=69.8 (%)

if the computer screen shows this image as calinda is downloading a file, how big is the file she’s loading ?

Answers

Answer:

the file is 20 kb

Step-by-step explanation:

16kb/80%

xkb/100%

1600=80%

80       80

20KB

If total employee benefits are calculated as a percentage of their gross pay, which of the following employees receives the largest percentage of their gross pay in employee benefits?

Answers

For this type of question, all you need to do is the following

- Find out the amount of Gross pay
- Find out the amount of total employee's benefit.
- Find out the difference between the two of them
- Find the percentage of that difference and compare it with the others

hope this helps

Solve for t(advanced rational equations)

Answers

t² -7 + 12t⁻² = 0

Multiply each side by t² :

t⁴ -7t² + 12 = 0

This is a quadratic equation in the variable ' t² '.
For just a moment, to avoid confusion, let U = t².
Then the equation is

U² - 7U + 12 = 0
whence
(U - 4) (U - 3) = 0
and
U = 4   and   U = 3 .

Now we can go back to ' t² ' in place of U :

t² = 4
t = +2  and  t = -2

t² = 3
t = +√3  and  t = -√3

                                       
t^2-7+12t^(-2)=0\n t^4-7t^2+12=0\n t^4-3t^2-4t^2+12=0\n t^2(t^2-3)-4(t^2-3)=0\n (t^2-4)(t^2-3)=0\n (t-2)(t+2)(t^2-3)=0\n t=2 \vee t=-2 \vee t=-√(3)\vee t=\sqrt3