A bear is sitting at rest on a tricycle. The bear then starts to accelerate uniformly at a rate of 2.5m/s2. How long will it take the bear to reach a velocity of 15 m/s?
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Answer:
15 m/s
Explanation:
Initial velocity, u = 0
Acceleration of bear, a = 2.5 m/s²
We need to find time taken by bear to reach a velocity of 15 m/s.
Acceleration is equal to the rate of change of velocity. So,
It will take 6 seconds to reach a velocity of 15 m/s.
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A skier pushes her ski poles against the ground. She begins to move across the snow. Earth does not seem to move. Identify the action and reac-tion forces in this example, and explain why the skier moves but Earth does not seem to.
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The position of an object moving along a line at any time t 2 0 is given by the function s(t) = t3 – 9t2 + 18, where s is measured in feet and t is measured in seconds. A) Find the velocity of the particle at t = 4.
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Answers
Answer:
5N
Explanation:
To get the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle, we will have to resolve the force perpendicular to the wrench. Torque is the turning effect of a body or force about a point. It is similar to moments.
Torque = Force * radius
Note that the force must be perpendicular to the wrench. On resolving the force perpendicularly to the wrench, we will have to resolve the force to the vertical.
Fy = Fsinθ
Fy = 10sin30°
Fy = 10 * 0.5
Fy = 5N
Torque = Fy * r
Given Fy = 5N and r = 20cm = 0.2m
Torque = 5 * 0.2
Torque = 1Nm
Hence the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle is 5N
B
C
D
Answers
Answer:
A
Explanation:
The figure shows the electric field produced by a spherical charge distribution - this is a radial field, whose strength decreases as the inverse of the square of the distance from the centre of the charge:
More precisely, the strength of the field at a distance r from the centre of the sphere is
where k is the Coulomb's constant and Q is the charge on the sphere.
From the equation, we see that the field strength decreases as we move away from the sphere: therefore, the strength is maximum for the point closest to the sphere, which is point A.
This can also be seen from the density of field lines: in fact, the closer the field lines, the stronger the field. Point A is the point where the lines have highest density, therefore it is also the point where the field is strongest.
B) Thermosphere
C) Exosphere
D) Lithosphere
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The natural frequency of the automobile in the vertical direction is 3.52 Hertz
Static equilibrium
Static equilibrium refers to the physical state in which the components of a system are at rest and the net force acting through the system is equal to zero.
In static equilibrium:
kd = mg
where;
k = effective spring constant of the spring.
mg = the weight of the car
d = static deflection.
also K = mω²
where ω is angular velocity
m is mass
Thus, mω²d = mg
ω²d = g
ω = √g/d
ω = g/d
ω = √9.8/0.02
ω = 22.15 rad/sec
Converting to Hertz unit for frequency
1 rad/s = 0.1591 Hertz
22.14 rad/s = 22.14 * 0.1591
22.14 rad/s = 3.525 hertz
Therefore, the natural frequency of the automobile in the vertical direction is 3.52 Hertz
Learn more about natural frequency at: brainly.com/question/11753773
Answer:Frequency = 3.525 Hertz
Explanation:In static equilibrium, kd =mg
Where k= effective spring constant of the spring.
mg= The weight of the car.
d= static deflection.
Therefore, w =SQRTg/d
w = SQRT 9.81/0.02
w= 22.15 rad/sec
Converting to Hertz unit for frequency
1 rad/s = 0.1591
22.15rad/s=?
22.15 × 0.1591= 3.525 hertz