The basic functions which are important for the survival of an organism include processes such as homeostasis, nutrient absorption and distribution in body, reproduction, and defense against injury or pathogens.
There are usually nine organ systems present in an animal which includes skeletal, muscular, nervous, endocrine (hormonal), digestive, respiratory, circulatory, excretory (urinary), and reproductive system. Each of these systems perform a specific function.
The Skeletal system provides the body structure and is responsible for the movements of different body parts. The muscular system is made up of all the muscles which are present in the body, these help in connecting different body parts to the skeletal system. The nervous system consist of the brain and the spinal cord, this system is responsible for coordinating different functions in the body.
The endocrine system is responsible for secreting hormones which are responsible for the growth and development of body. The digestive system helps in absorbing the energy present in the food and distributing the energy. The circulatory system is responsible for the circulation of gases and different molecules across the body through blood vessels.
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Answer:
The heart pumps blood through the circulatory system, delivering needed materials (glucose, oxygen) and picking up waste (carbon dioxide) from cells all over the body. Organs systems work together to efficiently and effectively provide all body cells with their basic needs to carry out life functions.
Archaeopteryx
Enantiornithes
Paleognathae
Answer:
A bird or feathered dinosaur is Archaeopterix.
Explanation:
Archeopteryx is an extinct genus of primitive birds, with intermediate characters between feathered dinosaurs and modern birds.
Archeopteryx lived in the Upper Jurassic Period about 150 million years ago, in what is now southern Germany, during a time when Europe was an archipelago of islands in a shallow warm tropical sea, much closer to the equator of what is now.
Answer:
A bird or feathered dinosaur if Archaeopteryx.
Answer:
(its C)
if its right tell me!
Males are the only ones who exhibit the condition because it is X-linked and recessive (unaffected parents have affected progeny). Given that the feature is rare, it is assumed that no one possesses it.
Pedigree is a family treediagram with standardized symbols. A pedigree reveals the connections between family members.
It identifies the members of a family who have particular geneticpathogenic variations, features, and diseases as well as their current health.
Because the disease is X-linked and recessive, only males can have it (unaffected parents have affected progeny). It is considered that no one has the feature because it is rare.
When one marries into the family, they inherit the recessive allele. Because the boy inherited a Y chromosome from his father, the first couple has no chance of having a child who is afflicted.
The possibility that the secondcouple will have afflicted sons is 50%, but there is no chance that they will have affected daughters.
All of the third couple'sdaughters will be carriers even though they have no chance of conceiving an impacted child.
Thus, this can be concluded regarding the given situation.
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Your question seems incomplete, the missing image is:
Answer:
esiska black is da right answer ahaha
Explanation:
b) If Sally's parents have another child what is theprobabilty that this child will have alkaptonuria?
c) If Sally marries a man with alkaptonuria, what is theprobability that their child will have alkaptonuria?
If Sally marries a man with alkaptonuria, there is a 50% chance that their child will have alkaptonuria.
The genotype of an individual refers to the sum total of genes that the individual received from its parents. Since Sally has a normal metabolism, Sally is Aa. Sally's mother is Aa while Sally's father and brother are aa.
If Sally parents have another child, using the Punnet square method, there is a 50% chance that the child will have alkaptonuria. If Sally marries a man with alkaptonuria, there is a 50% chance that their child will have alkaptonuria.
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a) Genotypes: : Aa (carrier of the alkaptonuria allele) ,Mother: Aa (carrier of the alkaptonuria allele)Father: aa (has alkaptonuria)Brother: aa (has alkaptonuria)
b) If Sally's parents have another child:The probability of the child having alkaptonuria (aa genotype) is 25%.The probability of the child being a carrier (Aa genotype) is 50%.The probability of the child having normal metabolism (AA genotype) is 25%.
c) If Sally marries a man with alkaptonuria (aa genotype):The probability of their child having alkaptonuria (aa genotype) is 50% (as Sally is a carrier).The probability of the child being a carrier (Aa genotype) is 50%.
The probability of the child having normal metabolism (AA genotype) is 0% (as the husband has alkaptonuria).
Sally: Aa (normal metabolism carrier)
Mother: Aa (normal metabolism carrier)
Father: aa (alkaptonuria)
Brother: aa (alkaptonuria)
b) If Sally's parents have another child:
Probability of the child having alkaptonuria (aa genotype) is 25%.
Probability of the child being a carrier (Aa genotype) is 50%.
Probability of the child having normal metabolism (AA genotype) is 25%.
c) If Sally marries a man with alkaptonuria (aa genotype):
Probability of their child having alkaptonuria (aa genotype) is 50% (as Sally is a carrier).
Probability of the child being a carrier (Aa genotype) is 50%.
Probability of the child having normal metabolism (AA genotype) is 0% (as the husband has alkaptonuria).
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Answer:
Explanation:
A) to determine amino acid sequence of the protein produced by that gene. We will use cDNA library, we will hybridize given part of DNA sequence ( as this part only contains exon part). Than we will isolate the hybridize part and translate this sequence using generic coding table.
B) for determine presence or absence of introns in gene used isolated cDNA in first question. Now we will add this cDNA to DNA library. Here cDNA due to complementary mature binds with DNA. If cDNA binds completely with gene with out looping part of gene it shows that gene is having only exons .
And if along with hybridization part some looped part present in between-- it shows both exons and intron are present.
C) for determining alternative splicing we will use cDNA library.
d) to determine length of mature mRNA which includes both the UTR and poly A sequence we will go for cDNA cloning and look for particular cDNA complementary to DNA segments. And later we isolate that cDNA and examine its whole length
E) to determine which cells in the tribble body express this particular mRNA . We use fluorescent tagged small DNA part provided. Then we will add this DNA probe to supplied tribes. The cells which are expressing , will have cDNA will bind to probe and florescent can be detected. Cells which are not expressing that gene, here probe will not bind and no fluorescence.
F) to determine that whose blood strain is this. We will do VBTR profiling . Which VNTR profiling similar to belief stain help to determine which blood stain is this.
acid
to a DNA solution causes a change
in its absorbance.
Answer:
See the answer below
Explanation:
The addition of acid to a DNA causes a change in its absorbance because acids tend to destroy the covalent bonds that hold the base pairs in DNA together.
In other words, acids, especially at high concentrations, denatures DNA. Denatured DNAs exhibit hyperchromic reaction, that is, they show increased absorbance as a result of less interaction between the bases.