a school built a new gym the gym is rectangular and has an area of 6,000 square feet. if the gym is 100 feet long how wide is it

Answers

Answer 1

Answer:

Using the formula of the area of the rectangle, the required width of the rectangular gym is 60 ft.

What is a rectangle?

A rectangle is a quadrilateral with four right angles in the Euclidean plane. It can also be defined as an equiangular quadrilateral since equiangular indicates that all of its angles are equal; or a parallelogram containing a right angle.

An enclosed 2-D shape called a rectangle has four sides, four corners, and four right angles (90°).

A rectangle has equal and parallel opposite sides.

A rectangle has two dimensions—length and width—because it is a two-dimensional form.

So, we know that the area is:

6000 ft²

And the length is 100 ft.

Then the width will be:

Area = l * w

6000 = 100 * x

x = 6000/100

x = 60 ft

Therefore, using the formula of the area of the rectangle, the required width of the rectangular gym is 60 ft.

Know more about a rectangle here:

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Which is bigger 40% of 120 or 1/4 of 200

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1/4 of 200 is bigger because it is 50 and 40% of 120 is 48

Use the table below to answer the following question.2. Do the values in the table represent a linear function? If so, what is the function rule?
(1 point)
The values do not show a linear function.
Yes, the values show a linear function: y = x + 4.
Yes, the values show a linear function: y = 2x + 2.
Yes, the values show a linear function: y = 2x.

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Y = 2X

Plug in values from the table

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6m + 4 = 8m

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Multiply each side by 2 :

8 = 4m

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Find two consecutive whole numbers that √129 lies between. A. 10 and 11 B. 11 and 12 C. 12 and 13 D. 13 and 14

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Two bicyclists leave the center of town at the same time. One heads due north and the other heads due west. Later, the two cyclists are exactly 25 mi apart. The cyclist headed north has traveled 5 mi farther than the cyclist going west.How far has the cyclist going west traveled?

Answers

Answer:

Distance traveled by bicyclist traveling west = 15 miles

Step-by-step explanation:

These two cyclists travel at angle 90°

Relative displacement can be calculated using Pythagoras theorem.

Let d be the distance traveled by bicyclist traveling west

Distance traveled by bicyclist traveling north = d + 5

$25^2=d^2+(d+5)^2\n\nd^2+d^2+10d+25=625\n\n2d^2+5d-600=0\n\nd^2+5d-300=0\n\nd=(-5\pm √(5^2-4* 1* (-300)))/(2* 1)\n\nd=(-5\pm √(25+1200))/(2)\n\nd=(-5\pm √(1225))/(2)\n\nd=(-5\pm 35)/(2)\n\nd=15miles\texttt{ or }d=-20miles$

Negative displacement is not possible.

Hence d = 15 miles

Distance traveled by bicyclist traveling west = d = 15 miles

This situation is represented in annex.
From Pythagorean theorem you've got equation:
$x^2+(x+5)^2=25 \n \n \hbox{From formula} \ \ \ (a+b)^2 = a^2+2ab+b^2: \n \n x^2+x^2+10x+25=25 \n 2x^2+10x=0 \n \n \hbox{Factor out} \ \ 2x: \n 2x(x+5)=0 \n \n \hbox{So you've got:} \n \n x_1=0 \n x_2=-5$

There isn't any solutions where x>0, so this situation is IMPOSSIBLE.

Did you write correctly this question....?

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