Answers
Answer:
3
Explanation:
10⁰ = 1 because anything to the power of 0 is 1.
3×1= 3
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A golf pro swings a golf club, striking a golf ball that has a mass of 55.0 g. The club is in contact with the ball for only 0.00340 s. After the collision, the ball leaves the club at a speed of 46.0 m/s. What is the magnitude of the average force (in N) exerted on the ball by the club?
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What was the main idea of Malthus theory of population
Answers
To solve this problem we will apply the concept related to the lens power with which farsightedness can be corrected. Mathematically this value is given by the relationship,
Here,
f =focal length
In turn, said expression can be exposed in terms of the distance of the object and the image as:
Here,
p = Object Distance ( By convention is 25cm)
q = Image distance
Replacing we have,
Therefore the power lens that is needed to correct for farsightedness is +2.67D
Answers
Answer:
Time = 1.61 seconds
Explanation:
Using the equation displacement of a trajectory motion in the y plane
Y = u t sin ů - ½gt²....equation 1 where
Y= vertical displacement =4.1
U = initial velocity = 15m/s
g = acc. Due to gravity = 10m/s
Ů = angle of trajectory = 45
t = time to reach fan on its way down
Sub into equ 1
4.1 = 15t sinů - ½ * 10t²
4.1 = 10.61t - 5t²
Solve using quadratic formula
t =[-B±( -B² -4AC)^½]/2A....equation 2
Where A = 5, B=10.61, C =4.1
Substitute A,B,C into equ2
t = (10.61±5.53)/10
t = 0.508seconds or 1.61seconds
Since it is on its way down t= 1.61 seconds
Answers
Answer:
160 Hz , 240 Hz , 400 Hz
Explanation:
Given that
Frequency of forth harmonic is 320 Hz.
Lets take fundamental frequency = f₁
f₁=80 Hz
Frequency of first harmonic = f₂
f₂=2 f₁
f₂ =2 x 80 = 160 Hz
Frequency of second harmonic = f₃
f₃= 3 f₁=3 x 80 = 240 Hz
Frequency of fifth harmonic = f₅
f₅= 5 f₁= 5 x 80 = 400 Hz
Three frequencies are as follows
160 Hz , 240 Hz , 400 Hz
Final answer:
The resonant frequencies of a string depend on its length, tension, and linear mass density. For a string resonating in four loops at 320 Hz, three possible smaller frequencies could be 160 Hz, 106.7 Hz, and 80 Hz.
Explanation:
When a string resonates, it vibrates at certain frequencies called its resonant frequencies. The resonant frequencies of a string depend on factors such as its length, tension, and linear mass density. In this case, the string resonates in four loops at a frequency of 320 Hz.
Three other possible resonant frequencies at which the string could vibrate with smaller loops include:
- 160 Hz: This is half the frequency of the given resonant frequency, which means the string vibrates with twice the number of loops.
- 106.7 Hz: This is one third of the given resonant frequency, which means the string vibrates with three times the number of loops.
- 80 Hz: This is one fourth of the given resonant frequency, which means the string vibrates with four times the number of loops.
Learn more about Resonant frequencies here:
#SPJ3
Answers
Answer:
69.68 N
Explanation:
Work done is equal to change in kinetic energy
W = ΔK = Kf - Ki =
W =
where m = mass of the sprinter
vf = final velocity
vi = initial velocity
W = workdone
kf = final kinetic energy
ki = initial kinetic energy
d = distance traveled
Ftotal = total force
vf = 8m/s
vi= 2m/s
d = 25m
m = 60kg
inserting parameters to get:
W = ΔK = Kf - Ki =
= 39.7
we know that the force the sprinter exerted F sprinter, the force of the headwind Fwind = 30N
Answer:
Force exerted by sprinter = 69.68 N
Explanation:
From work energy theorem, we know that, work done is equal to change in kinetic energy.
Thus,
W = ΔK = Kf - Ki = (1/2)m•(v_f)² - (1/2)m•(v_i)² - - - - eq(1)
Now,
Work done is also;
W = Force x Distance = F•d - - - (2)
From the question, we are given ;
v_f = 6 m/s
v_i = 2 m/s
d = 25m
m = 62 kg
Equating equation 1 and 2,we get;
(1/2)m•(v_f)² - (1/2)m•(v_i)² = F•d
Plugging in the relevant values to obtain ;
(1/2)(62)[(6)² - (2)²] = F x 25
31(36 - 4) = 25F
992 = 25F
F = 39.68 N
The force the sprinter exerts backward on the track will be the sum of this force and the headwind force.
Thus,
Force of sprinter = 39.68 + 30 = 69.68N
Answers
Explanation:
The reason for the more concentration of carbon dioxide in the atmosphere of Venus than in the Earth -
On the Earth , most amount of the carbon dioxide is in the ocean water and in sea sediments .
Considering Venus , in the planet Venus , there is no Ocean water , hence , carbon dioxide can not get dissolved into the water , hence , it is found in the atmosphere .
So , the escape velocity for carbon dioxide on Mars is smaller than Venus .
Answers
Explanation:
The relation between resistance and resistivity is given by :
is resistivity of material
l is length of wire
A is area of cross section of wire
Resistivity of a material is the hidden property. If one wire has 3 times the length of the other, then it doesn't affect its resistivity. Hence, the resistivity of two wires is