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Solve: the quantity 3x minus 15 divided by 2 = 4x

Answers

Answer 1
Answer:

Answer:

x=-3

Step-by-step explanation:

(3x-15)/2 = 4x

Multiply each side by 2

(3x-15)/2 *2= 4x*2

3x-15 = 8x

Subtract 3x from each side

3x-15-3x = 8x-3x

-15 = 5x

Divide each side by 5

-15/5 = 5x/5

-3 =x
Answer 2
Answer:

Answer:

X=-3

Step-by-step explanation:

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What is the y-coordinate of the point that divides the directedline segment from J to K into a ratio of 2:3?

K(8,11)

J(-3,1)


*7

*-6

*5

*-5

Answers

Answer:

(D)5

Step-by-step explanation:

Given the point J(-3,1) and K(8,11).

The line segment that divides the segment from J to K in any given ratio can be determined using the formula.

P(x,y)=\left((mx_2+nx_1)/(m+n) ,(my_2+ny_1)/(m+n)\right)

In the given case:

(x_1,y_1)=(-3,1), (x_2,y_2)=(8,11), m:n=2:3

Since we are to determine the y-coordinate of the point that divides JK into a ratio of 2:3, we have:

(my_2+ny_1)/(m+n)=(2*11+3*1)/(3+2)\n\n=(22+3)/(5)\n\n=(25)/(5)\n\n=5

The y-coordinate of the point that divides the directed  line segment from J to K into a ratio of 2:3 is 5.

The correct option is D.

Answer:

The answer is actually C(5) not D

Step-by-step explanation:

If EN=16 and BN=20 what is the scale factor of the dilation?

Answers

The scale factor of the dilation is approximately 1.25.

To find the scale factor of the dilation, we need to compare the corresponding side lengths of the original figure and the dilated figure.

Let's consider the two corresponding side lengths:

Original side: EN = 16 units

Dilated side: BN = 20 units

The scale factor (k) of the dilation is the ratio of the corresponding side lengths in the dilated figure to the original figure. It can be calculated using the formula:

Scale factor (k) = Dilated side length / Original side length

Substituting the given values:

k = 20 / 16 ≈ 1.25

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Simran waited 3 1/2 hours for her car to get repaired.what is 3 1/2 written as a decimal

Answers

3.5 is 3 and one half




Fun fact
Banana

Answer:

3.5

Step-by-step explanation:

im a sophmore and i know this

The Food and Drug Administration (FDA) is a U.S. government agency that regulates (you guessed it) food and drugs for consumer safety. One thing the FDA regulates is the allowable insect parts in various foods. You may be surprised to know that much of the processed food we eat contains insect parts. An example is flour. When wheat is ground into flour, insects that were in the wheat are ground up as well. The mean number of insect parts allowed in 100 grams (about 3 ounces) of wheat flour is 75. If the FDA finds more than this number, they conduct further tests to determine if the flour is too contaminated by insect parts to be fit for human consumption. The null hypothesis is that the mean number of insect parts per 100 grams is 75. The alternative hypothesis is that the mean number of insect parts per 100 grams is greater than 75. Is the following a Type I error or a Type II error or neither? The test fails to show that the mean number of insect parts is greater than 75 per 100 grams when it is. Group of answer choices Type I error Type II error

Answers

Answer:

Type II error

Step-by-step explanation:

Let's remember the definition of Type I error and Type II error:

A type I error is the rejection of a true null hypothesis, this means that we would get a "false positive" with this error.

A type II error is the non rejection of a not true null hypothesis, this error would give us a "false negative".

In this problem the mean number of insect parts per 100 grams is 75. However, the test fails to show that this number is greater than 75 when it is, this means that the test is not detecting these insect parts and therefore is giving a "false negative"

Thus, this is a Type II error.

Final answer:

This situation is an example of a Type II error. This occurs when the test fails to reject the null hypothesis when it should be rejected. In this context, it means the test was unable to detect the actual average content of insect parts is higher than the allowable limit.

Explanation:

The situation presented constitutes a Type II error in the field of hypothesis testing in statistics. A Type II error occurs when the tester fails to reject the null hypothesis when it should be rejected. In this context, it means the test failed to show that the mean number of insect parts per 100 grams is greater than 75, when in fact, it is. This can potentially mean allowing more contaminated flour into the market because the test did not pick up on the true mean being higher than 75 insect parts per 100 grams.

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A spinner has 3 equal sections that are purple, green, and blue. What is the probability of not landing on blue?

Answers

Answer:

P(not landing on blue section)=2/3

Step-by-step explanation:

Not landing on blue section = landing on one of the other sections

the remaining sections are 2 each one has a P=1/3

2 × 1/3 = 2/3

Answer:

66%

Step-by-step explanation:

2 divided by 3= 0.666666666 which is then converted to percent (66%)

A carnival ride holds 30 people at a time. In one hour,220 people went on the ride. It was full each time
except the last. How many times was the ride
completely filled?

Answers

Answer:

7

Step-by-step explanation:

Final answer:

Given that a ride can hold 30 people at once, and that 220 people in total went on the ride, one minus the total number of people (to account for the last ride not being completely filled) divided by the total ride capacity gives us 7.3. This means the ride was completely filled 7 times.

Explanation:

To find out how many times the carnival ride was completely filled, we will divide the total number of people who went on the ride, by the maximum number of people the ride can hold at a time. However, we know that the last ride was not completely full, meaning there was at least one less person on the ride than it can hold, so we need to subtract 1 from the total number of people before proceeding.

So, we have: (220 people - 1) ÷ 30 people = 7.3. Since a ride can't be partially filled (i.e. 0.3 of a ride), we know that the ride was filled completely 7 times, and the remaining 0.3 represent the last, not completely filled ride.

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