Answer:
It is an irrational number (also it's spelled square root)
Answer:
irrational
Step-by-step explanation:
but
is irrational so all the expression is irrational
Answer:
27 square units
Step-by-step explanation:
To use Heron's formula, you need to know that "s" represents half the perimeter.
s = (11 +6 +9)/2 = 13
Then the area is given by the formula as ...
A = √(13(13 -11)(13 -6)(13 -9)) = √(13·2·7·4) = √728
A ≈ 26.98 ≈ 27 . . . square units
Answer:
27 units
Step-by-step explanation:
correct answer on edge
Answer:
We know that range is the set of outputs that shown on the y-axis of the graph, so we must find the endpoints of the graph on the y-axis. When we look, we get the endpoints -6 and 10, so we know that this is the range, and so we represent this in an expression:
-6 < y < 10
Step-by-step explanation:
f(x), because an increasing quadratic function will eventually exceed an increasing exponential function
g(x), because an increasing exponential function will eventually exceed an increasing quadratic function
f(x), because an increasing exponential function will always exceeds an increasing quadratic function until their graphs intersect
g(x), because an increasing quadratic function will always exceeds an increasing exponential function until their graphs intersect
Answer:
Option 2 is correct.
Step-by-step explanation:
We have been given points of g(x) and f(x)
g(x) has ordered pairs (0,1) ,(1,2) ,(3,8) ,(5,32) and (6,64) this is an exponential function which is from the given points.
f(x) has ordered pairs (0,1) ,(1,2) ,(3,10) ,(5,26) and (6,37) this is a quadratic function
We will put these values in the quadratic function which is:
Taking (0,1)
c=1
Now, taking (1,2)
(1)
Now, taking (3,10)
(2)
Now, solving the equation (1) and (2) we get:
a=1 and b=0
Hence, the function
Please look at the attachment for the graph
We can see that the g(x) an exponential function will eventually exceed the increasing quadratic function
Therefore, option 2 is correct.
Answer:
graph:
find -18, and draw an arrow going right