Answer:
2. 135
3. 8
4. 9/49 or 0.18367346…
5. b2/125
Step-by-step explanation:
( I couldn't see what b was equal to if you showed it. And the b2 is b squared)
y = and y =
y = and y =
y = and y =
The solution of the quadratic equation (4y – 3)² = 72 are y = (6√2 + 3)/4 and y = (-6√2 + 3)/4
Quadratic equations are equation that has a degree of 2. Given the quadratic equation as shown:
(4y – 3)² = 72
Take the square root of both sides
√(4y – 3)² = ±√72
4y -3 = ±√72
4y - 3 = ±6√2
4y = ±6√2 + 3
y = (6√2 + 3)/4 and y = (-6√2 + 3)/4
Hence the solution of the quadratic equation (4y – 3)² = 72 are y = (6√2 + 3)/4 and y = (-6√2 + 3)/4
Learn more on quadratic equation here: brainly.com/question/17987697
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Answer:
30 minutes
Step-by-step explanation:
Just look at the minutes only. Since you need 4 o'clock to 4:30, its only 30 minutes.
Answer:
30 minutes
Step-by-step explanation:
All you have to do is subtract 4:30 and 4:00 and get 30 minutes.
The height of the office building is 99.2 meters
The given parameters are:
The above parameters can be represented using the following equivalent ratio
Express as fraction
So, we have:
Multiply both sides by 170
Rewrite as:
Hence, the building is 99.2 meters tall
Read more about equivalent ratios at:
Answer:
99.17m
Step-by-step explanation:
In the diagram, Marquis is at Point A and the flag pole is length DE, the building is of length BC.
Triangles ADE and ABC are therefore similar right triangles.
Applying this,
[TeX]\frac{|DE|}{|AE|}=\frac{|BC|}{|AC|}[/TeX]
[TeX]\frac{35}{60}=\frac{|BC|}{170}[/TeX]
|BC|=170*35÷60
|BC|=99.17m
NEED HELP ASAP PLEASE!
Answer:
<1 = 54
Step-by-step explanation:
< CAB = <1 + <2
We have to assume that AP is a perpendicular bisector or we cannot solve the problem.
That would mean that <1 = <2
11x+9 = 6x+6x
11x+9 = 12x
Subtract 11x from each side
9 = 12x-11x
9 =x
We want <1
<1= 6x
<1 = 6*9
<1 = 54