Andrew 550
Jason 380
Cathy 720
Jessica 710
Robert 550
The table gives the scores of 6 students from a class of 25 in a competitive exam. The point estimate of the mean score for the students is _____-
. (Round off your answer to the nearest tenth.)
Answer
593.3
Explanation
Mean is also called average. It represents the average mark of a given data.
For the question above, you to add all the marks of the students then you divide by the number of students.
Mean = (650+550+380+720+710+ 550)÷6
= 3,560 ÷ 6
=593.3333
Answer to the nearest tenth = 593.3
The point estimate of the meanscore for the students is 593.34 if the number of observation is 6.
It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.
We know,
Mean = (sum of observation)/(number of observation)
Sum of scores = 650+550+380+720+710+550 = 3560
Number of observation = 6
Mean = 3560/6 = 593.33 = 593.34
Thus, the point estimate of the meanscore for the students is 593.34 if the number of observation is 6.
Learn more about the mean here:
#SPJ5
Answer: she should use 5/8 cups i think
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
How many problems of each point value are on the test?
Answer:
Option 4 is correct that is both apply
Step-by-step explanation:
We have given the triangle we have to tell which postulate SSS or SAS to use to prove
ΔABC=ΔAED
We can use both of them
Case1: Since, three of the sides are equal that is
AB=AE
AC=AD
BC=ED
Which means SSS can be used
Since, SSS is side side side
Case2: Since one angle and two sides are equal
AB=AE
AC=AD
And ∠BAC=∠EAD
Which means SAS can be used
Since, SAS is side angle side
Therefore, Option 4 is correct that is both apply.
Answer: both apply
Step-by-step explanation:
SAS congruence postulate says that if two sides and the included angle of a triangle are congruent to two sides and the included angle of other triangle then the two triangles are said to be congruent.
In the given triangles ΔABC and ΔAED , we have
∠BAC ≅ ∠EAD
AC ≅ AD
BE ≅ DE
If AB ≅ AE , then we have sufficient things to proof that ΔABC ≅ ΔAED by SSS congruence postulate .
i.e. for AC ≅ AD , BE ≅ DE and AB ≅ AE [all three sides are congruent]
ΔABC ≅ ΔAED by SSS congruence postulate.
Also, If AB ≅ AE , then we have sufficient things to proof that ΔABC ≅ ΔAED by SAS congruence postulate .
i.e. for AC ≅ AD [Side]
∠BAC ≅ ∠EAD [included angle]
AB ≅ AE [Side]
⇒ ΔABC ≅ ΔAED by SAS congruence postulate.
Hence, we can apply both postulates to prove triangles congruent .