Answer:
Instructions are below.
Explanation:
Giving the following information:
Unit sales price $ 30
Variable cost per unit 6
Fixed costs per year 360,000
To calculate the contribution margin ratio, we need to use the following formula:
Contribution margin ratio= contribution margin / selling price
Contribution margin ratio= (30 - 6) / 30
Contribution margin ratio= 0.8
The break-even point in dollars formula is:
Break-even point (dollars)= fixed costs/ contribution margin ratio
Break-even point in units= 360,000 / 0.8
Break-even point in units= $450,000
Now, the desired profit is $440,00:
Break-even point (dollars)= (fixed costs + desired profit) / contribution margin ratio
Break-even point (dollars)= (360,000 + 440,000) / 0.8
Break-even point (dollars)= $1,000,000
Finally, the margin of safety:
Sales= 60,000*30= $18,000,000
Margin of safety= (current sales level - break-even point)
Margin of safety= 18,000,000 - 450,000
Margin of safety= $17,550,000
Answer:
The correct answer is D.
Explanation:
Giving the following information:
The fixed cost per unit is $7 when 25,000 units are produced and $5 when 35,000 units are produced.
Total fixed costs= 7*25,000= 175,000
Total fixed costs= 5*35,000= 175,000
Fixed costs= $175,000
Answer:
120
Explanation:
Data provided in the question:
Number of workdays in a year = 250
Demand, D = 7,500 units
Ordering costs, F = $25.00 per order
Carrying costs, C = $9.00
Lead time = 4 days
Now,
Reorder point = Lead Time in days × Average Daily Demand
also,
Average Daily Demand = Demand ÷ Number of workdays in a year
= 7500 ÷ 250
= 30
Thus,
Reorder point = 4 × 30
= 120
Answer:
$73,600
Explanation:
A learning curve is a correlation between a learner's performance on a task and the number of attempts or time required to complete the task; this can be represented as a direct proportion on a graph
The last unit will be 22nd unit .
Using learning curve table ,
Time required to build 22nd unit = 3125.49 hours
labour cost to build 22nd unit ( $20 per hour ) = $20 x $3125.49
labour cost to build 22nd unit = $62509.80
Using learning curve table ,
material and equipment cost to build 22nd unit = $11090.67
Therefore,
total cost to build the last unit = Labour cost + Material and equipment cost total cost to build the last unit = $62509.80 + $11090.67
total cost to build the last unit = $73600.47
Learning rate for labour hours ( L1) = Time for 2nd unit / Time for 1st unit
Learning rate for labour hours ( L1) = 4500/5000
Learning rate for labour hours ( L1) = 0.90
Learning rate for material and equipment usage
Learning rate for material and equipment usage = Material and equipment cost for 2nd item / Material and equipment cost for 1st item
Learning rate for material and equipment usage = 24000/30000
Learning rate for material and equipment usage = 0.80 or 80 %
Answer: Ethical Egoism
Explanation:
The theory of Ethical Egoism posits that people or entities are well within their rights to act in a manner that benefits their best interest and in so doing are being good in their own right.
The small bank acted in such a manner that it left itself unexposed to risk whilst still making quite a huge profit. The small bank pursued its own interests and so followed the moral theory of Ethical Egoism.
The bank is operating under the moral theory of Moral Egoism. It acts in its own best interest by making large profits off the home loans and offloading the long-term risk.
The bank's actions seem to align with the Moral Egoism theory. This theory suggests that an entity, in this case, the bank, acts in its own best interest. Offering home loans at extremely low initial rates turns in large profit for the bank, which is its main interest. However, offloading the risk of these loans onto another bank marks the bank's primary focus on their well-being rather than the consequences for their customers in the long run. These customers may struggle if the larger bank they deal with lacks flexibility in difficult situations.
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Answer: Stabilize the economy
Explanation:
Solution and Explanation:
Depreciation expense is calculated as follows:
Depreciation expense = Cost of machine minus residul value divide useful life of asset
= (159600 - 0) / 8 = 19950
Thus, annual depreciation expense is $19950
Partial year depreciation expense = Anuual depreciation multiply period
= 19950 mulitply 0.5 = $9975
Thus, partial depreciation expense for the 01st january 2023 to July 1, 2023 is $9975
the jorunal entry is as follows:
Depreciation account Dr. 9975 ($)
Accumulated depreciation Cr. 9975 ($)
1. if machine is sold for $79800 cash
Cash 79800
Accumulated depreciation 89775
gain on sale of machinery 9975
Machinery 159600
2. If machine is sold for $67032
Cash 67032
Accumulated depreciation 89775
loss on sale of machinery 2793
Machinery 159600