Length of the rectangular photo = 22 inches
Width of the rectangular photo = 20 inches
Since, width of the frame outside the photo = x inches
Therefore, increase in length and width of the photo with frame = (x + x)
= 2x inches
Length of the photo with frame = (22 + 2x) inches
Width of the photo with frame = (20 + 2x) inches
Combined Area of the photo in the frame = Length × Width
= (22 + 2x)(20 + 2x)
= 22(20 + 2x) + 2x(20 + 2x)
= 440 + 44x + 40x + 4x²
= 4x² + 84x + 440
Therefore, polynomial representing the combined area of the photo in the frame will be (4x² + 84x + 440) square inches.
If width of the frame = 4 inches
Combined area of the photo = 4(4)² + 84(4) + 440
= 840 square inches
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Answer:
A is 4x^2+84x+440 and B=840 square inches
Step-by-step explanation:
A is 4x^2+84x+440 and B=840 square inches
The task for a is to write a polynomial in standard form that represents the combined area of the photo and the frame. First, lets start with the bottom of the picture and frame. On the bottom, you have 2x+ 22 inches. Then the side of the picture and frame is 2x+20 inches. Writing in polynomial form, it would be (2x+22)(2x+20). You would get 4x^2+84x+440 since you are using the FOIL method. Now for part b, we know that the width of the frame(or x) is 4 inches. Now we plug that into the equation. 84x is 84x4. 84x4=336 x^2 is 16. There are four of those as you can see in the equation so 16x4=64
336+64=400 inches Frame= 400 inches
400 inches plus the picture(440 inches) = 840 square inches.
A 23/27
B 31/45
C 14/27
D 1/3
1/2 ÷ 3/4=
Plz answer quickly!
6-(-12)=18
1/2 ÷ 3/4=2/3