Answer: x ≈ 9
Step-by-step explanation:
Near the end of the picture 8.553364=x
x ≈ 9
Step-by-step explanation:
18/26
27/39
36/52
45/65
An equivalent fraction for a/b is found by multiplying the numerator and denominator by a common integer (n)
Using the probability concept, it is found that there is a 0.7273 = 72.73% probability that the fruit is an APPLE or has an EVEN number.
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem:
Then, the probability is:
0.7273 = 72.73% probability that the fruit is an APPLE or has an EVEN number.
A similar problem involving the probability concept is given at brainly.com/question/15536019
Answer:
8 in 11 or 0.7272
Step-by-step explanation:
Between 6 apples. 2 lemons and 3 melons, Will has a total of 11 fruits in his garden. There are three apples labeled with even numbers (2,4 and 6), one melon (2) and one lemon (2), for a total of five fruits.
The probability that a randomly selected fruit is an APPLE or has an EVEN number is given by the probability that it is an apple, P(A), added to the probability that it is even, P(E), minus the probability that it is an even apple, P(A and E):
There is a 8 in 11, or a 0.7272 chance that the fruit is an APPLE or has an EVEN number.
Answer:
Hey! the answer is e
Step-by-step explanation:
If you were to draw two lines intercepting each other, one point would be the same, right?
Here there is line AE, and line DE. The repeated point is E, which means it's the intersection.
I can't add visuals at the moment, but imagine like an x, a being on one end, d on the other, and e in the middle.
Hope this helps!
Answer:
80% confidence interval for the average age of people who attend U of O football games is [42.795 , 44.604].
Step-by-step explanation:
We are given that a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years.
So, the pivotal quantity for 80% confidence interval for the population average start up cost is given by;
P.Q. = ~
where, = sample average age = 43.7 years old
= sample standard deviation = 7 years
n = sample of attendees = 100
= population average age of people
So, 80% confidence interval for the average age of people, is ;
P(-1.2915 < < 1.2915) = 0.80
P(-1.2915 < < 1.2915) = 0.80
P( < < ) = 0.80
P( < < ) = 0.80
80% confidence interval for = [ , ]
= [ , ]
= [42.795 , 44.604]
Therefore, 80% confidence interval for the population average age of people who attend U of O football games is [42.795 , 44.604].