Answer:
it's most likely D because 80 plus 80 equals 160 plus 20 is 180
2x-y=0
*x=-1,y=-2
*x=1,y=2
*x=2,y=1
*x=-2,y=-1
Answer:
Solving this system of linear equations by elimination we get x=-1 and y=-2
Option 1 is correct option.
Step-by-step explanation:
We are given equations:
We need to solve by Elimination method.
Elimination method: Add or subtract the equations to get an equation in one variable.
Rearranging the equation 1 we get
Add eq(1) and eq(2)
So, after eliminating y we get x=-1
Now finding y by putting x in eq(1)
We get y=-2
So, solving this system of linear equations by elimination we get x=-1 and y=-2
Option 1 is correct option.
Step-by-step explanation:
Step 1: Simplify the equation
7.22−4.9(5.1+3.1)
=51.84−4.9(5.1+3.1)
=51.84−(4.9)(8.2)
Step 2: Solve and subtract the numbers
=51.84−40.18
=11.66
Explanation in words:
- To solve this equation, the first step is to simplify the equation and at the end, the answer will result as = 51.84-(4.9)(8.2).
- To solve this equation, the second step is to solve that equation and break it down so we will have to subtract and at the end, the answer for this whole equation will result as = 11.66.
Answer:
= 11.66
Hope this helps.
6.6
0.6
-1.5
3
Answer:
6.6
Step-by-step explanation:
-12
0
1
8
What is the value of x when f (x) = 4?
Answer:f(4)= 12
Step-by-step explanation:
Treat f(x) as y, y=2x + 4, y=12
Answer:
x = 0
Step-by-step explanation:
Given f(x) = x² + 4 and f(x) = 4, then equating
x² + 4 = 4 ( subtract 4 from both sides )
x² = 0 , thus
x = 0
Answer:
CA.
Step-by-step explanation:
To find the gradient (slope) of the line 2y - 3x = 6, we need to rewrite the equation in slope-intercept form (y = mx + b), where "m" represents the gradient. Here's how:
2y - 3x = 6
First, isolate "y" on one side of the equation:
2y = 3x + 6
Next, divide both sides by 2 to solve for "y":
y = (3/2)x + 3
Now we can see that the gradient (slope) of the line is (3/2).
Now, let's analyze the three lines AB, BC, and CA, formed by the points A(-5, -12), B(11, -4), and C(7, 6).
The gradient (slope) of the line AB can be calculated using the coordinates of points A and B:
Gradient of AB = (Change in y) / (Change in x) = (-4 - (-12)) / (11 - (-5)) = 8 / 16 = 1/2
The gradient (slope) of the line BC can be calculated using the coordinates of points B and C:
Gradient of BC = (Change in y) / (Change in x) = (6 - (-4)) / (7 - 11) = 10 / (-4) = -5/2
The gradient (slope) of the line CA can be calculated using the coordinates of points C and A:
Gradient of CA = (Change in y) / (Change in x) = (-12 - 6) / (-5 - 7) = -18 / (-12) = 3/2
Now, we compare the gradients of the lines AB, BC, and CA to the gradient of the line 2y - 3x = 6 (which is 3/2). We see that the line CA has the same gradient (3/2) as the line 2y - 3x = 6.
So, the line CA is parallel to the line 2y - 3x = 6.