What is the probability of selecting a cherry piece? Write answer as a reduced fraction.

Answers

Answer 1

Answer:

Answer:6/14 or to round it up by 1/14 and make it simplified it would be 1/2

Step-by-step explanation:

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Is the red line a radius or diameter of the circle

Answers

The diameter of the circle would be a line going through the center of the circle connecting to both sides.

The radius of a circle would be a line only going to the the center, or in other words, half the circle.

I hope this makes sense!

A rumor spreads through a small town. Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor. a. Write the differential equation satisfied by y in terms of proportionality k.
b. Find k (in units of day−1, assuming that 10% of the population knows the rumor at time t=0 and 40% knows it at time t=2 days.
c. Using the assumptions in part (b), determine when 75% of the population will know the rumor.
d. Plot the direction field for the differential equation and draw the curve that fits the solution y(0)=0.1 and y(0)=0.5.

Answers

Answer:

The answer is shown below

Step-by-step explanation:

Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor.

$(dy)/(dt)\ \alpha\ y(1-y)$

$(dy)/(dt)=ky(1-y)$

where k is the constant of proportionality, dy/dt = rate at which the rumor spreads

$(dy)/(dt)=ky(1-y)\n(dy)/(y(1-y))=kdt\n\int\limits {(dy)/(y(1-y))} \, =\int\limit {kdt}\n\int\limits {(dy)/(y)} +\int\limits {(dy)/(1-y)} =\int\limit {kdt}\n\nln(y)-ln(1-y)=kt+c\nln((y)/(1-y)) =kt+c\ntaking \ exponential \ of\ both \ sides\n(y)/(1-y) =e^(kt+c)\n(y)/(1-y) =e^(kt)e^c\nlet\ A=e^c\n(y)/(1-y) =Ae^(kt)\ny=(1-y)Ae^(kt)\ny=(Ae^(kt))/(1+Ae^(kt)) \nat \ t=0,y=10\%\n0.1=(Ae^(k*0))/(1+Ae^(k*0)) \n0.1=(A)/(1+A) \nA=(1)/(9) \n$

$y=((1)/(9) e^(kt))/(1+(1)/(9) e^(kt))\ny=(1)/(1+9e^(-kt))$

At t = 2, y = 40% = 0.4

c) At y = 75% = 0.75

$y=(1)/(1+9e^(-0.8959t))\n0.75=(1)/(1+9e^(-0.8959t))\nt=3.68\ days$

If three out of every fourteen trick-or-treaters that came to your house last Halloween were dressed as pirates, what proportion of trick-or-treaters were not dressed as pirates?

Answers

Answer:

Explanation:

Given that three out of every fourteen trick-or-treaters were dressed as pirates

The proportion of the tick-or-treaters that were not dressed as pirates is the subtraction of the proportion of the people d

Dressed as pirates = 3/14

Not dressed as pirates = 14/14 - 3/14

= 11/14

What is 9 + 2x = -x + 3

Answers

Answer:

x=-2

Step-by-step explanation:

Help with this math question please thanks

Answers

For this case, what we should do is use the given equation.
A = P (1 + r) ^ t
Substituting values we have:
3900 = 1100 * (1 + 0.04) ^ t
Clearing t we have:
(1.04) ^ t = (3900) / (1100)
log1.04 ((1.04) ^ t) = log1.04 ((3900) / (1100))
t = log1.04 ((3900) / (1100))
t = 32.3 years
Answer:
the time will be:
t = 32.3 years

Someone help pls!!! Thanks

Answers

Answer:

The answers are A and C

Step-by-step explanation:

A is correct because -16 is on the left of the number line.