A glacier grew g feet over winter. It shrank 25 feet in summer.if the total change was -10 feet how much had the glacier grown in winter

Answers

Answer 1
Answer: You would have to add 25 and -10 together

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PLEASE HELP ASAP!!!!! What is the ratio of the volumes of a cylinder and a cone have the same base radius and height? Explain. PLEASE HELP ASAP

Answers

The ratio of the volume of cylinder and cone is 3:1
Because the volume of:
Cylinder = The area of base x height
Cone     = 1/3 The area of base x height

Explain why a change from 20 to 40 is a 100% increase, but a change from 40 to 20 is a 50% decrease.Increasing 20 to 40 is the same as increasing 20 by c. So, it is a 100% increase. Decreasing 40 to 20 is the same as decreasing 40 by one-half of c. So, it is a 50% decrease.
I don't understand how to fill in the blanks.

Answers

I believe the answer you are looking for is:

Increasing 20 to 40 is the same as increasing 20 by 20 (or itself), so it is a 100% increase. Decreasing 40 to 20 is the same as decreasing 40 by 1/2 or by 20. So it is a 50% increase.

Basically, when going from 20 to 40, the number is being doubled, and when youre going from 40 to 20 you are cutting the number in half.

Answer:

The first blank is 20 and the second is actually 40

Step-by-step explanation:

YOU ARE WELCOME

(343×7^2×100)÷(10^3×7^2×3^3)=

Answers

Step-by-step explanation:

(343 *  {7}^(2)  * 100) / ( {10}^(3)  *  {7}^(2)  *  {3}^(3) ) \n  \n  = ( {7}^(3)  *  {7}^(2)  *  {10}^(2) ) / ( {10}^(3)  *  {7}^(2)  *  {3}^(3) ) \n  \n  = ( {7}^(3 + 2)  *  {10}^(2) ) / ( {10}^(3)  *  {7}^(2)  *  {3}^(3) ) \n  \n  = ( {7}^(5)  *  {10}^(2) ) / ( {10}^(3)  *  {7}^(2)  *  {3}^(3) ) \n  \n  =  \frac{{7}^(5)  *  {10}^(2) }{{10}^(3)  *  {7}^(2)  *  {3}^(3) }  \n  \n  =  \frac{ {7}^(3) }{10 *  {3}^(3) }  \n  \n  =  (343)/(270)  \n

2 ( 4a - 12 ) + 3a = 6a + 1

Answers

2(4a-12)+3a=6a+1
8a-24+3a=6a+1
11a-24=6a+1
5a=25 /:5
a=5

Answer:

a = 5

Step-by-step explanation:

1/3(2x-4)+5=-2/3(x+1)

Answers

(1)/(3) (2x-4)+5=- (2)/(3)(x + 1) \n \n  (2x-4)/(3) +5=- (2)/(3) (x + 1) \n \n  (2x-4)/(3) +5=- (2(x + 1))/(3) \n \n 2(x - 2) + 15 = -2(x + 1) \n \n 2x - 4 + 15 = -2x - 2 \n \n 2x + 11 = -2x - 2 \n \n 2x + 11 + 2x = -2 \n \n 4x + 11 = -2 \n \n 4x = -2 - 11 \n \n 4x = -13 \n \n x = - (13)/(4) \n \n Answer: \fbox {x = -13/4} \ or \ \fbox {-3.25}
(1)/(3)(2x-4)+5=-(2)/(3)(x+1)\n\n3 *[ (1)/(3)(2x-4)+5] = 3* -(2)/(3)(x+1)\n\n(2x-4) + 15 = -2(x+1)\n\n2x - 4 + 15 = -2(x+1)\n\n2x + 11 = -2(x+1) \n\n2x + 11 = -2x -2\n\n4x + 11 = -2\n\n4x = -13\n\n\boxed{\bf{x = -(13)/(4)}}

Can someone help me out!!!??? Please

Answers

Answer:

  see below

Step-by-step explanation:

The two marked points are equidistant from their average, which is ...

  (-3 +9)/2 = 6/2 = 3

The distance they are from that average is 9-3 = 3 -(-3) = 6.

So, you want an expression that is equivalent to ...

  |x -3| = 6

Subtracting 1 from both sides of this equation gives you the one seen in choice B:

  |x -3| -1 = 5