The distance in meters of a basket suspended on a spring to a tabletop below is dependent on the number of steel bearings in the basket. The function representing this relationship is d(m) = 7 – 2m, where d(m) represents the distance in meters, and m represents the number of steel bearings in the basket. Which set represents the evaluation of the function d(m) = 7 – 2m when m ∈ {0, 1, 2, 3}?

Answers

Answer 1

Answer:

The set representing the evaluation of the function d(m) for m ∈ {0, 1, 2, 3} is {7, 5, 3, 1}.

What is the set of the evaluation?

To evaluate the function d(m) = 7 - 2m for different values of m, we simply need to substitute each value of m from the given set {0, 1, 2, 3} into the function and compute the corresponding d(m) values.

Let's calculate d(m) for each value of m:

For m = 0:

d(0) = 7 - 2(0) = 7

For m = 1:

d(1) = 7 - 2(1)= 7 - 2 = 5

For m = 2:

d(2) = 7 - 2(2) = 7 - 4 = 3

For m = 3:

d(3) = 7 - 2(3) = 7 - 6 = 1

So the set representing the evaluation of the function d(m) for m ∈ {0, 1, 2, 3} is {7, 5, 3, 1}.

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Answer 2

Answer:

Answer:

do u have a pic or something

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THE EXPRESSION (TAN THETA) (CSC THETA) IS EQUAL TO?

Answers

$tan\theta\cdot csc\theta=(sin\theta)/(cos\theta)\cdot(1)/(sin\theta)=(1)/(cos\theta)=sec\theta$

Which numbers are solutions of the equation?

|5 – 4x| – 3 = 4

Answers

$|5-4x|-3=4\ \ \ /+3\n\n|5-4x|=7\iff5-4x=7\ \vee\ 5-4x=-7\n\n-4x=7-5\ \vee\ -4x=-7-5\n\n-4x=2\ /:(-4)\ \vee\ -4x=-12\ /:(-4)\n\nx=-(2)/(4)\ \vee\ x=(-12)/(-4)\n\nx=(1)/(2)\ \vee\ x=3$

From 126 ounces to 48 ounces as a percent

Answers

We have (126 - 48 )/126 = 62.5%;

What is the result if you divide –12x8y8 by 3x4y2?a. 4x4y6
b. 4x2y4
c. –4x2y4
d. –4x4y6

Answers

When dividing two numbers with the same base but with different powers, you subtract the second power from the first and keep the base. So in our case, -12*x^8*y^8 / 3*x^4*y^2 = -4*x^4*y^6. The correct answer is d.

Answer:

option d is correct

$-4x^4y^6$

Step-by-step explanation:

Using exponent rules:

$(a^n)/(a^m) = a^(n-m)$

Given that:

If you divide $-12x^8y^8$ by $3x^4y^2$

⇒ $(-12x^8y^8)/(3x^4y^2)$

⇒ $(-4x^8y^8)/(x^4y^2)$

Using exponent rules, we have;

⇒ $-4x^(8-4)y^(8-2)$

⇒ $-4x^4y^6$

Therefore, If you divide $-12x^8y^8$ by $3x^4y^2$ we get; $-4x^4y^6$

Solve the triangle.A = 33°, a = 19, b = 14
Select one:
a. B = 23.7°, C = 143.3°, c ≈ 23.3
b. B = 23.7°, C = 123.3°, c ≈ 17.5
c. Cannot be solved
d. B = 23.7°, C = 123.3°, c ≈ 29.2

Answers

Using the sine law to find the value of angle B:

a / sin A = b / sin B
19 / sin 33 = 14 / sin B

B = arcsin (14 * sin 33 / 19 )
B = 23.66° = 23.7°

Since the sum of all interior angles of a triangle is 180°, we can solve for angle C like so:

C = 180° - 23.7° - 33°
C = 123.3°

Using sine law to solve for side c:

a / sin A = c / sin C
c = (a*sin C)/sin A
c = 29.157 = 29.2

Therefore, among the choices, the correct answer is D.

Answer:

Took the test

B=23.7 degrees

C=123.3 degrees

c=29.2

At 10 A.M. a plane leaves Boston, Massachusetts, for Seattle, Washington, a distance of 3000 mi. One hour later a plane leaves Seattle for Boston. Both planes are traveling at a speed of 300 mph. How many hours after the plane leaves Seattle will the planes pass each other?

Answers

Answer:

The plane from Seattle will pass the plane from Boston after 4.5 hours of its departure from the Seattle.

Step-by-step explanation:

Plane-1 = Boston, Massachusetts - Seattle, Washington at 10:00 AM

Plane-2= Seattle, Washington - Boston, Massachusetts at 11:00 AM

Speed of plane-1 = 300 mile/hour

Distance covered by plane-1 in 1 hour = 300 mile/h × 1 h = 300 mile

Distance between plane-1 and plane 2 after 1 hour :

= 3000 mile - 300 mile = 2700 mile

Let the distance covered by plane-1 after 1 hour be x in t time where it will pass plane-2.

Let the distance covered by plane-2 be y in t time where it will pass plane-1.

x + y = 2700 ...[1]

Speed of plane-1 = 300 mile/hour

$300 mile/h=(x)/(t)$ ..[2]

Speed of plane-2 = 300 mile/hour

$300 mile/h=(y)/(t)$ ..[3]

Putting value of t from [2] in [3];

$t=(x)/(300 mile/h)$

$300 mile/h=(y)/((x)/(300 mile/h))$

$(x)/(300 mile/h)=(y)/(300 mile/h)$

x = y

In [1] put x = y

y + y = 2700 miles

2y = 2700 miles

y = 1,350 mile

For the value of t, put the value of y in [3]:

$t=(1,350 mile)/(300 mile/h)=4.5 hour$

The plane from Seattle will pass the plane from Boston after 4.5 hours of its departure from the Seattle.

Final answer:

The Boston plane travels for 1 hour before the Seattle plane sets off, covering 300 miles. The remaining distance between them is then 2700 miles. Both planes flying towards each other at a combined speed of 600 mph cover this distance in 4.5 hours.

Explanation:

The subject of this question is a relative speed math problem. The Boston plane travels for an hour before the Seattle plane leaves. So, the Boston plane covers a distance of 300 miles (1 hour * 300 mph). This means that at the time the Seattle plane leaves, the total remaining distance between them is 2700 miles (3000 miles - 300 miles).

Now we consider both planes flying towards each other. In this case, the relative speed is the sum of their speeds, thus 600 mph (300 mph + 300 mph). So, to cover the remaining 2700 miles, it will take 4.5 hours (2700 miles ÷ 600 mph).

Therefore, the airplanes will meet each other 4.5 hours after the Seattle plane leaves.

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