Find the value of the variable.
66

32

29

43

Answers

Answer 1

Answer:

Answer:

The correct answer is x = 32.

Step-by-step explanation:

To solve this problem, we must remember the concept of supplementary angles. Two angles that are supplementary together make an angle of 180 degrees (a straight line).

In this case, we can see that inside the triangle, we will have an angle of 80 degrees. We know this because the angle at the top of the triangle is supplementary with the angle measuring 100 degrees, so its measure should be 180-100 = 80 degrees.

On the lower right hand of the triangle, a similar rationale can be applied. The angle inside of the triangle must measure 68 degrees, since it is supplementary to an angle measuring 112 degrees, and 180-112=68.

Finally, to solve this problem, we must remember that the sum of the three interior angles of a triangle should be 180 degrees. This lets us set up the following equation:

80+68+x = 180

Now, we can solve this equation. Our first step is to simplify the left side of the equation by adding together the constant terms.

148 + x = 180

Next, we should subtract 148 from both sides of the equation.

x = 180-148

x = 32

Therefore, the correct answer is x = 32 degrees.

Hope this helps!

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PLZ HURRY IT'S URGENT!!!What is the slope of the line?

y=3
options:

0

1

3

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Answers

Answer:

There is no x or number with an x (example: y= 2x+3, the 2 would be the slope)

Answer:

Step-by-step explanation:

Suppose a quiz contains 20 true/false questions. You know the correct answer to the first 10 questions. You have no idea of the correct answer to questions 11 through 20 and decide to answer each using the coin toss method. Calculate the probability of obtaining a total quiz score of at least 85%

Answers

Answer:

0.1719

Step-by-step explanation:

Given that:

A quiz contains 20 questions and 10 questions have been answered rightly

We are to determine the probability of getting a total quiz score of 85%

i.e 0.85 (20) = 17

Let's not forget that 10 is correctly answered out of 17. that implies that we only have 7 more questions to make a decision on.

where;

n = 10,

p + q = 1, 0.5 + q = 1

q = 1 - 0.5

q = 0.5

Let X be the random variable that follows the binomial distribution. Then ;

$P(X = x) =(^n_x) p^x q^(n -x)$

where x = 7

$P(X \geq 7) =P(X=7)+P(X=8)+P(X=9)+P(X=10)$

$P(X \geq 7) =(^(10)_7})\ 0.5^7 \ 0.5 ^(10-7) + (^(10)_(8))\ 0.5^8 \ 0.5 ^(10-8)+(^(10)_9})\ 0.5^9 \ 0.5 ^(10-9)+ (^(10)_(10)})\ 0.5^(10) \ 0.5 ^(10-10)$

P(X ≥ 7) = 0.1719

What is the portion that repeats of the repeating decimal of seven thirteenths

Answers

Answer:

hi want to talk to me ?

Step-by-step explanation:

Answer:

7 13/100

Step-by-step explanation:

Simplify.

7.52 - 2.9 × 1 + 0.8

Answers

Answer:

5.42

Step-by-step explanation:

PEMDAS

$7.52 - 2.9 * 1 + 0.8\n-2.9*1= -2.9\n7.52-2.9+0.8\n7.52-2.9= 4.62\n4.62+0.8= 5.42\nAnswer : 5.42$

Answer:

5.42

It is this because 7.52-2.9 is equal to 4.62 plus 0.8 equals 5.42.

Jerry weighs 105 pounds if a male brown bear weighs 11 times as much what is the brown bear's weight

Answers

That boy weighs 1155

Final answer:

To find out the brown bear's weight, we multiply Jerry's weight (105 pounds) by 11, because the bear weighs 11 times more than Jerry. This gives a result of 1155 pounds.

Explanation:

This problem is an example of multiplication, demonstrating how to compare and calculate weights. Given that Jerry weighs 105 pounds and that a male brown bear weighs 11 times more than Jerry, we must multiply Jerry's weight by 11 to find out how much the bear weighs.

Therefore, the calculation would be: 105 pounds (Jerry's weight) x 11 (the amount a male brown bear weighs compared to Jerry) = 1155 pounds. Hence, the brown bear's weight is 1155 pounds.

Learn more about Multiplication here:

brainly.com/question/5992872

#SPJ2

Compute the area of the region D bounded by xy=1, xy=16, xy2=1, xy2=36 in the first quadrant of the xy-plane. Using the non-linear change of variables u=xy and v=xy2, find x and y as functions of u and v.x=x(u,v)= ?

y=y(u,v)=?

Find the determinant of the Jacobian for this change of variables.

∣∣∣∂(x,y)/∂(u,v)∣∣∣=det=?

Using the change of variables, set up a double integral for calculating the area of the region D.

∫∫Ddxdy=?

Evaluate the double integral and compute the area of the region D.

Area =

Answers

Answer:

53.7528

Step-by-step explanation:

Notice that when

$xy = 1 ,\,\,\, xy = 16 , \,\,\, xy^2 = 1 \,\,\,, xy^2 = 36 \n\n$

If you set

$u = xy , v = xy^2$

as they suggest, then

$y = (v)/(u)} \,\,\,\, \text{and} \,\,\,\, \n\n{\displaystyle x = (u)/(y) = (u)/(v/u) = (u^2)/(v)$

Then

${\diplaystyle (\partial(x,y))/(\partial(u,v))} =\det \begin{pmatrix} 2u/v && -u^2/v^2 \n -v/u^2 && 1/u \end{pmatrix} = (1)/(v) }$

Therefore

$\iint\limits_(D) dx\,dy = \int\limits_(1)^(36)\int\limits_(1)^(16) (1)/(v) \, du \, dv = 15 \ln(36) = 53.7528$

A Jacobian matrix is formed by the first partial derivatives of a multivariate function that utilizes a training algorithm, and further calculation as follows:

Jacobian:

To evaluate the integral, cover the bounds, the integrand, and the differential area dA.

Transform the four equations in terms of u and v, notice that $u= xy \ \ and \ \ xy = 1, xy = 16$

implies that $1\leq u \leq 16.$

Similarly, $v= xy^2\ \ and\ \ xy^2= 1 , xy^2= 25$ implies that $1 \leq v \leq 25$

so write this integration region as $S= {(u,v) |1 \leq u \leq 18, 1 \leq v \leq 25}.$

Translate the equations from uv - plane to xy- plane. It is obtained by solving,

$u= xy, y= xy^2 \n\n\left.\begin{matrix}u=xy & \n v=xy^2& \end{matrix}\right\} \to \left.\begin{matrix}u^2=x^2y^2 & \n v=xy^2& \end{matrix}\right\} \n\n\to x=(u^2)/(v), y=(v)/(u)$

Convert dA part of the integral , using is $dA= |(\partial (x,y))/(\partial(u,v))| dudv.$

That is, $dA= \begin{vmatrix}(\partial x)/(\partial u) & (\partial x)/(\partial v)\n (\partial y)/(\partial u) & (\partial y)/(\partial v) \end{vmatrix} \ du dv \n\n$

Sampule the partial derivatives to find the Jacobian.

$dA=\begin{vmatrix}(2u)/(v) &-(u^2)/(v^2) \n -(v)/(u^2) &(1)/(u) \end{vmatrix} \ dudv\n\n=[((2u)/(v)) ((1)/(u)) -(- (u^2)/(v^2))(-(v)/(u^2))]\ du dv\n\n=((2)/(v)- (1)/(v)) \ dudv\n\n=(1)/(v)\ du dv\n\n$

The Jacobian the transformation is $dA= (1)/(v)dudv$

The region is $S={(u,v) |1\leq u \leq 16, 1\leq v\leq 25}.$

Rewrite the integral, using the transformation: $S,\ x=(u^2)/(v) =, y=(v)/(u) \ \ and\ \ dA=(1)/(v) dudv\n\n\int\int_R 1dA =\int \int_S (1)/(v)\ dudv= \int^(25)_(1) \int^(16)_(1) \ (1)/(v) \ dudv\n\n$