MATHEMATICS HIGH SCHOOL

Find the sum 93.5+8.7

Answers

Answer 1

Answer:

Answer:

102.2 is your answer

hope this helped you

please mark as the brainliest (ㆁωㆁ)

Answer 2

Answer: A:

93.5
+ 8.7
———
102. 2

Always make sure before adding to place ur decimal down before u add. It’ll help u a lot.

Please mark brainliest :/

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The difference in cost between a large bag of chips and a small bag of chips was 90 cents. Alicia bought 5 large bags and 3 small bags of chips for her party and spent 17.22. What was the cost of a small bag or chips.please show the steps and process

Answers

X-small bag
x+0.9-large bag

5(x+0.9)+3(x)=17.22
5x+4.5+3x=17.22
8x=12.72
x=1.59

the small bag costs 1.59 while the big bag costs 2.49

hopw this helps :)

Simplify

-2 x (4) -3 x (-5)

Answers

Hey there!

-2 x (4) -3 x (-5)
= -2(4) - 3(-5)

= -8 - (-15)

= -8 + 15
= 7

Therefore, your answer is: 7

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

nvm i got it wrong

sdasdasdas

Solve the following linear inequality:

3(x + 4) ≥ 5x – 123

Answers

$3(x+4)\geq5x-123\n3\cdot x+3\cdot4\geq5x-123\n3x+12\geq5x-123\ \ \ \ /-12\n3x\geq5x-135\ \ \ \ /-5x\n-2x\geq-135\ \ \ /:(-2) < 0\ then\$

$3(x + 4) \geq 5x - 123 \n 3x+12\geq5x-123\n 2x\leq135\n x\leq(135)/(2)$

An alloy weighing 40 lbs. is 10% tin. The alloy was made by mixing a 15% tin alloy and a 8% tin alloy. How many pounds of each alloy (to the nearest tenth) were used to make the 10% alloy?lbs. of the 15% alloy and lbs. of the 8% alloy.

Answers

Let the weight of 15% tin be x.

So the weight of the 8% tin will be: (40 - x), since the total weight is 40 lbs

Using the mixture formula:

w1*p1 + w2*p2 = w*p

Where w1 = weight of the first percentage, p1 = First Percentage

w2 = weight of the second percentage, p2 = Second Percentage

w = Final weight, p1 = Final Percentage

0.15*x + 0.08(40 - x) = 40*0.1

0.15x + 3.2 - 0.08x = 4

0.15x - 0.08x = 4 - 3.2

0.07x = 0.8

x = 0.8/0.07

x ≈ 11.429

Recall the 15% was made with x, which is ≈ 11.429

Recall the 8% was made with (40-x) ≈ (40 - 11.429) ≈ 28.571

So the 10% tin of the 40 lbs was made with ≈11.4 lbs of the 15% tin and ≈28.6 lbs of the 8% tin

x=15% alloy
y=8% alloy
x+y=40
y=40-x
0.15x+0.08y=40*0.10
0.15x+0.08(40-x)=40*0.1
times 100 both sides for easy
15x+8(40-x)=400
15x+320-8x=400
7x+320=400
minus 320 from both sides
7x=80
divide both sides by 7
x=80/7
x+y=40
80/7+y=280/7
y=200/7
aprox
x=11.4lb
y=28.6lb

11.4lb of 15%
28.6lb of the 8%
what????

Find the mode for the data set. 8.3, 8.7, 4.5, 6.9, 3, 4.2, 11.7, 4

4

6.9

8.3

no mode

Answers

8.3 ; 8.7 ; 4.5 ; 6.9 ; 4.2 ; 11.7 ; 4

Arrange in order from least to greatest.

4 ; 4.2 ; 4.5 ; 6.9 ; 8.3 ; 8.7 ; 11.7

The mode is the number that appears the most in the data set. Every number only appeared once. So. there is no mode in the data set.

NO MODE.

What is the discriminant of the quadratic equation 2x + 5x2 = 1?–18
–16
22
24