Check all the equations that apply to meet the Segment AdditionPostulate in segment OQ. OP=6X+5,PQ=4x and OQ=45
Check all the equations that apply to meet the Segment - 1

Answers

Answer 1
Answer:

Answer:

Options (2) and (5)

Step-by-step explanation:

Given in the question,

Length of OQ = 45

OP = (6x + 5)

PQ = 4x

By segment addition postulate,

Length of a segment OQ = length of segment OP + length of segment PQ

45 = 6x + 5 + 4x

10x + 5 = 45

10x = 45 - 5

10x = 40

x = (40)/(10)

x = 4

Therefore, Option (2) and Option (5) are the correct options.


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Adiya said that the first step to solving the quadratic equation x2 + 6 = 20x by completing the square was to divide 6 by 2, square that value, and add the result to both sides. Is Adiya’s solution method correct? Explain.

Answers

Answer:

No, it is incorrect.

Step-by-step explanation:

The quadratic equation is

x^2+6 = 20x or x^2-20x+6=0. To complete square we take the coefficient of x divided by 2, square that value and add the result to both sides. In the equation given the number to do the process is 20, not 6, then the solution method is incorect.

Answer:

NO it is not correct

Step-by-step explanation:

Adiya’s method is not correct. To form a perfect square trinomial, the constant must be isolated on one side of the equation. Also, the coefficient of the term with an exponent of 1 on the variable is used to find the constant in the perfect square trinomial. Adiya should first get the 20x term on the same side of the equation as x2. Then she would divide 20 by 2, square it, and add 100 to both sides.

Multiply the following equation: (2x-7)(x+3).

Answers

FOIL
first
outer
inner
last
example if you had
(a+b)(c+d)
first a times c
outer a times d
inner b times c
last b times d

(2x-7)(x+3)
first 2x times x=2x^2
outer 2x times 3=6x
inner -7 times x=-7x
last -3 times 3=-21

add them
2x^2+6x-7x-21
2x^2-x-21

Which expression is equivalent to - 3 x (4/- 5)?a. (- 3 x 4) / 5
b. - 3/5 x 4
c. - 3/- 5 x 4
d. (- 3 x 4) / (- 3 x (-5))

Answers

c expression equivalent to -3*(4/-5)

What is the perimeter of a tennis court 78ft long and 27ft wide?

Answers

210^2 is the answer  L*W

If 10 men can survive for 24 days on 15 cans of rations, how many cans will be needed for 8 men to survive for 36 days?

Answers

Answer:

18 cans

Step-by-step explanation:

Given : 10 men can survive 24 days on 15 cans

To find : how many cans for 8 men can survive for 36 days

Solution : 1 men can survive 1 day on= 15/ 10×24 = 15/240 cans

                8 men can survive 1 day = 8×15/240= 1/2 cans

                8 men can survive for 36 days = 36/2= 18 cans

therefore, 8 men can survive for 36 days = 36/2= 18 cans

10 men can survive for 24 days with 15 cans of ration
so , 1 man can survive for 1 day with 15/(10*24) cans of ration
so, 8 men can survive for 36 days with (15*8*36)/240 = 18 cans of raion

Which of the following recursive formulas represents the same geometric sequence as the formula an=2x3n-1

Answers

Hello,

a_(n)=2*3^(n-1)
a_(n-1)=2*3^(n-2)
(a_(n))/(a_(n-1))= (2*3^(n-1))/(2*3^(n-2))=3


Answer B