A local bowling alley charges $3 per game, plus $5 to rent a pair of shoes. Write an algebraic expression that models the cost of renting one pair shoes and bowling g games.

Answers

Answer 1
Answer:

Answer:

5+3g

Step-by-step explanation:

This is because you pay $5 for shoes and $3 per game. Since the amount of games is unknown you put g.


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Simplify 3 1/5 + 4/16

Help asap!!!

Answers

Answer:

3 1/5 = 16/5

4/16 = 1/4

simply and find a common denominator, in this case it is 20. Multiply the top and bottom by the same number, to get the bottom to twenty. So, to get 5 to 20, you must multiply by 4, so you have to multiply the top by 4 too, which is 64. Do the same for the next fraction.  

16/5 = 64/ 20 (both x4)

1/4 = 5/20 (both x5)

now add

64/20 + 5/20 = 69/20

69/20 is the final answer because it cannot be simplified futher.

Answer:

Step-by-step explanation:

3 1/5 + 1/4

3 4/20 + 5/20

3  9/20

Round 4,339,908 to the ten thousand

Answers

I think it's 4,340,000 because the one thousands place was a 9 so u round up
It would be 4,340,000

In a crayon box there are 5 dark colors for every 8 light colors. If there are 20 dark colors, how many light colors are there?

Answers

5x4=20 so 8x4=32 32 light colors in the box
If we write this as a ratio then it would be 5:8. Now since there are 20 dark colors and also 5, what do 5 and 20 have in common... 5 times 4 is 20 so since we multiplied by 4 on dark colors do the same  to the light colors so 8 times 4 = 32. So the answer is 32 light colors

Solve 2cos^2x + cosx − 1 = 0 for x over the interval [0, 2 π ).a.π and π/3
b.π, π/3, and 5π/3
c.1 and 2π/3
d.1, 2π/3, and 4π/3
e.1, π/3, and 5π/3

Answers

the answer is (b) all this value of x satisfy the equation

Answer:

Option  B

Step-by-step explanation:

\pi ,(\pi )/(3), and (5\pi )/(3)

(a) Solve 7( k - 3 ) = 3k - 5 (b) Expand and simplify (2x + 3 )( x - 8)

(c) Solve 7 - 3= 2
                 4

Answers

a) 7(k-3)=3k-5\n 7k-21=3k-5\n 7k-3k=-5+21\n 4k=16\n k=\frac { 16 }{ 4 } \n k=4

b) (2x+3)(x-8)\n 2{ x }^( 2 )-16x+3x-24\n 2{ x }^( 2 )-13x-24

c) \frac { 7-3f }{ 4 } =2\n 7-3f=4\cdot 2\n 7-3f=8\n -3f=8-7\n -3f=1\n f=-\frac { 1 }{ 3 }
(a)\n7(k-3)=3k-5\n7(k)+7(-3)=3k-5\n7k-21=3k-5\ \ \ \ |add\ 21\ to\ both\ sides\n7k=3k+16\ \ \ \ |subtract\ 3k\ from\ both\ sides\n4k=16\ \ \ \ \ |divide\ both\ sides\ by\ 4\n\boxed{k=4}


(b)\n(2x+3)(x-8)=(2x)(x)+(2x)(-8)+(3)(x)+3(-8)\n\n=2x^2-16x+3x-24=\boxed{2x^2-13x-24}


(c)\n(7-3f)/(4)=2\ \ \ \ |multiply\ both\ sides\ by\ 4\n\n\not4^1\cdot(7-3f)/(\not4_1)=4\cdot2\n\n7-3f=8\ \ \ \ \ |subtract\ 7\ from\ both\ sides\n\n-3f=1\ \ \ \ \ |divide\ both\ sides\ by\ (-3)\n\n\boxed{f=-(1)/(3)}

The function h(t)=16t^2+144 represents the height , h(t) , in feet , of an object from the ground at t seconds after it is dropped . a realistic domain for this function is 1) -3 2) 0 3)0>h(t)<144
4) all real numbers

Answers

0≤h(t)≤144, which means that the height of the object can be between 0 and 144 feet, including those limits.