MATHEMATICS HIGH SCHOOL

A submarine that is 225 feet below sea level descends 67 feet and then ascends 110 feet. What is the location of the submarine compared to the sea level now?

Answers

Answer 1
Answer:

Answer:

182

Step-by-step explanation:

225+67-110
Answer 2
Answer:

Answer:

Step-by-step explanation:

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The floor of a rectangular deck has an area of 600 square feet. The floor is 20 feet wide. How long is the floor? A. 30 ft. B. 20 ft. C. 15 ft. D. 45 ft.

Answers

A. 30 ft
 The formula for the area of a rectangle is width x length = area. Knowing this formula, we can solve for the length by dividing the area by the width. 600 divided by 20 is 30.
The floor of a rectangular deck has an area of 600 square feet. The floor is 20 feet wide THE ANSWER IS (A) 30ft

Simplify 2m - [n - (m - 2n)].
-3m - n
3m - n
-3m - 3n
3m - 3n

Answers

you get 2m+m-3n which simplifies to    3m-3n

Simplify 8^5 x 8^4

A. 16^9
B. 8^20
C. 8^9
D. 64^9

Answers

Answer:

8^9

Step-by-step explanation:

8^9

Help pls
what is the slope intercept form of (-1,8) and (3,6)

Answers

Answer: y = 1/2x+15/2

Step-by-step explanation:

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If one letter is chosen at random from the word combed, what is the probability that the letter chosen will be a "d"? Fraction:

Decimal:

Percentage:

Likelihood of the event happening:

Answers

combed

The word combed has 6 letters, only 1 of which is the letter d.

So, the fraction is 1/6.

Dividing, if you round to the nearest hundredth, the decimal is 0.17.

Using the fraction again, if you multiply 1/6 by 100 to make it 100/6 and then round to the nearest hundredth, you get 16.67 %.

Likelihood of the event happening can be represented in any of the above ways shown above.

The formula for the area of a trapezoid is A=1/2h (b1+b2) express b1 in terms of A, h, and b2

Answers

A=1/2h(b₁+b₂)
1/2h(b₁+b₂)=A
(b₁+b₂)=2A/h
b₁=2A/h - b₂

answer: b₁=2A/h  -  b₂
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The area of a circle of radius r is given by A=\pi r^2A=πr 2 and its circumference is given by C=2\pi rC=2πr. At a certain point in time, the radius of the circle is r=8r=8 inches and the area of the circle is changing at a rate of \frac{dY}{dt}=\pi\sqrt{2} dt dA ​ =π 2 ​ square inches per second. How fast is the radius of the circle changing at this time
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