9 x (2 + 7) = (? x 2) + (? x 7)​

Answers

Answer 1
Answer: i believe the answer is 9x ( 2 + 7) = +9 x 2) + (9 x 7)

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Answers

Answer:

<2 ~= < 4 - Vertical Angles Theorem

<2 ~= <8 - Alternate Exterior Angles

<4 ~= <8 - Corresponding Angles Theorem

line I || line m - Transitive Property

A single-cell amoeba doubles every 3 days. how long would it take on amoeba to produce a population of about 10,000 amoebae?

Answers

2^n=10,000
2^14=10,000
d=3n
d=3(14)
d=42

d=days
n=number of times of reproduction

Final answer:

It would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.

Explanation:

To find out how long it would take for a single-cell amoeba to produce a population of about 10,000 amoebae, we need to calculate the number of times the amoeba doubles. Since the amoeba doubles every 3 days, we can find out the number of doubling periods it would take to reach 10,000 amoebae by dividing 10,000 by 2. This equals approximately 9.965, which means the amoeba would need to double about 9.965 times. Since we can't have a fraction of a doubling period, we can round it up to 10.

Each doubling period is 3 days, so to find out how long it would take, we can multiply the number of doubling periods (10) by the time interval for each doubling period (3 days). 10 x 3 = 30. Therefore, it would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.

Learn more about Exponential Growth

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the length of a rectangle is 9 centimeters more than the width. the area is 112 square centimeters. find the length and width of the rectangle

Answers

l = w + 9

lw = 112

Substitute l = w + 9 into the second equation

(w + 9)(w) = 112

w^2 + 9w - 112 = 0
(w+16)(w-7) = 0

w = -16
or
w = 7

we have to take the positive value, so  w = 7

l = w + 9
l = 7 + 9
l = 16

The length is 16, and the width is 7

here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)







Which equation has an a-value of 1, a b-value of –3, and a c-value of –5?0 = –3x – 5 + x2
0 = x – 3 – 5x2
0 = 3x – 5 – x2
0 = –3x + 5 – x2

Answers

Answer:

Option (a) is correct.

For given values a = 1 , b = -3 , c = -5 the quadratic equation is  0=-3x-5 + x^2

Step-by-step explanation:

Given : a = 1 , b = -3 , c = -5

We have to write the quadratic equation having a = 1 , b = -3 , c = -5 and choose the correct option.

The standard form of quadratic equation is ax^2+bx+c=0 , where a, b, c are constant integers.

Given : a = 1 , b = -3 , c = -5

Then Substitute, we get,

x^2-3x-5=0  

Thus, the obtained quadratic equation is same as option (a) 0=-3x-5 + x^2

Thus, For given values a = 1 , b = -3 , c = -5 the quadratic equation is0=-3x-5 + x^2 

Answer:

a

Step-by-step explanation:

A vehicle travels a distance of 5t4 − 10t2 + 6 miles in t + 2 minutes. What is the vehicle's speed?

Answers

Let distance be s and velocity be v
s = 5t⁴ - 10t² + 6
We know velocity is the change in distance per unit time, so
v = ds/dt
v = 20t³ - 20t

Answer:

The speed is 5t^3 - 10t^2 + 10t - 20 + 46/(t+2) miles per minute

Step-by-step explanation:

Reciprocal of 0.002894​

Answers