11. Una escuela telesecundaria tiene una pista de carreras que mide de kilómetro.Tres alumnas corrieron las siguientes distancias: Juanita: 1 vueltas, Esperanza
21 vueltas y Evelyn: 1650 m. ¿Cuántos metros corrieron Juanita y Esperanza?
¿Y cuántas vueltas dio Evelyn?

Answers

Answer 1

Answer:

Answer:

Juanita and Esperanza run 400 meters and 8400 meters respectively and Evelyn make 4.125 laps.

Step-by-step explanation:

The complete question is: A telesecundaria school has a race track that measures one kilometer.

Three students ran the following distances Juanita: 1 laps, Esperanza 21 laps and Evelyn: 1650 m. How many meters did Juanita and Esperanza run? And how many laps did Evelyn make?

As we know that 1 meter = 0.0025 laps

So, the number of laps Evelyn make = 1650 $*$ 0.0025

= 4.125 laps

Also, 1 lap = $(1)/(0.0025)$ meters

1 lap = 400 meters

So, the meters that Juanita run = 1 $*$ 400 = 400 meters

Similarly, the meters that Esperanza run = 21 $*$ 400

= 8400 meters

Hence, Juanita and Esperanza run 400 meters and 8400 meters respectively and Evelyn make 4.125 laps.

Answer 2

Answer:

Final answer:

Juanita ran 1 kilometer and Esperanza ran 21 kilometers. Evelyn ran 1 lap.

Explanation:

To find out how many meters Juanita and Esperanza ran, we need to add up their distances. Juanita ran 1 lap, which is equal to the length of the track. Since the track is 1 kilometer long, Juanita ran 1 kilometer. Esperanza ran 21 laps, so she ran 21 kilometers.

Evelyn ran 1650 meters. To find out how many laps Evelyn ran, we need to divide 1650 by the length of the track. Since the track is 1 kilometer long, Evelyn ran either 1 lap or 1.65 laps. However, we're told that Evelyn ran 1650 meters, so she ran 1 lap.

Learn more about Distances here:

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A walkway forms one diagonal of a square playground. the walkway is 16 m long. how long is a side of the playground?

Answers

Side of the playground would be : a²+a² = 16²

2a² = 256

a² = 128

a = √128

a = 11.31 m

Answer:

Step-by-step explanation:

Alright let's get started.

Please refer the diagram I have attached.

we have given a square playground whose diagonal is 16m.

Let us assume the side of the square is a.

Now, by applying the Pythagorean theorem we can find the side of the square which is:

$a^2+a^2=16^2$

$2a^2=256$

$a^2=(256)/(2)$

$a^2=128$

$a=√(128)$

$a=11.3$

Hence, the side of the playground is 11.3m. : Answer

What is the term of a 7-term geometric series if the first term is -11 the last term is -45,056 and the common ratio is -4

Answers

I assume you mean to ask how to find the sum of the seven terms?

You have

$a_2=ra_1$
$a_3=ra_2=r^2a_1$
$a_4=ra_3=r^3a_1$
...
$a_7=ra_6=r^6a_1$

So the sum is

$a_1+ra_1+r^2a_1+\cdots+r^6a_1=a_1(1+r+r^2+\cdots+r^6)=a_1*(1-r^7)/(1-r)$

You know that $a_1=-11$ and $r=-4$ , so the sum is equal to

$-4*(1-(-4)^7)/(1-(-4))=-13108$

Triangle PQR is right angle at Q. |PQ| = 3a cm and |QR| =4a cm. Determine |PR| in terms of a

Answers

A^2 + B^2=C^2 Pythagorean’s Theorem

(3a)^2 + (4a)^2 = C^2

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sqrt ((a^2(25)) = sqrt (C^2)

5a=C=|PR|

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Simplify 81^1/2
Please simplify and show steps

Answers

$a^(n)/(m)=\sqrt[m]{a^n}\n\n\n81^(1)/(2)=√(81)=9\n\n\n81^(1)/(2)=(9^2)^(1)/(2)=9^{2\cdot(1)/(2)}=9$

The expression 81⁽¹/²⁾ simplifies to 9.

To simplify the expression 81¹/², we can evaluate the squareroot of 81.

The square root of a number x is a value that, when multiplied by itself, gives x. In this case, we're looking for the number that, when squared, equals 81.

The square root of 81 is 9 since 9 x 9 = 81.

Therefore, 81⁽¹/²⁾ simplifies to 9.

In terms of steps, we can represent the process as follows:

1. Recognize that 81⁽¹/²⁾ represents the square root of 81.

2. Evaluate the squareroot of 81, which is 9.

3. Thus, 81^(1/2) simplifies to 9.

By simplifying the expression, we find that 81⁽¹/²⁾is equal to 9.

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Answers

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Tom is making a punch that contains 80% cranberry juice and the rest ginger ale. The punch has 2 liters of ginger ale. Part A: Write an equation using one variable that can be used to find the total number of liters of cranberry juice and ginger ale in the punch. Define the variable used in the equation and solve the equation. Hint: 0.8x represents the number of liters of cranberry juice in the punch. (5 points) Part B: How many liters of cranberry juice are present in the punch? Show your work.