Circle C is inscribed with 5 lines. Point C is at the center of the circle. 3 lines come out of point C and make points D, A, and B on the edge of the circle. Another line comes out of point C and goes past the edge to point E. Another line connects points D and A. Which geometric figures are drawn on the diagram? Check all that apply. Line segment C A Ray A C ∠ABC Circle C Ray B E ∠BCE Line segment A E

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Answer 1
Answer:

Answer:

A, B, D, F is the correct answer


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What is 7x to the third power minus 1 as a verbal expression

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This woud be Seven(x) cubed minus 1.

Solve 2x^2+15x-8=0 and 2x^2+8x-24=0 for x

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Answer:

X=.5

Step-by-step explanation:

put 2x^2+15x-8 into y1 of your calculator and 0 in y2 then second, trace, 5, enter, enter, enter. Then you have your answer

How would you find the zero of f (x)=16x^4 - 9x^2

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f (x) = 16x ^ 4 - 9x ^ 2 \n \n16x ^ 4 - 9x ^ 2=0\n \nx^2(16x^2-9)=0 \n \nx^2 =0 \ \ or \ \ 16x^2-9=0\n \n x=0 \ \ or \ \ (4x-3)(4x+3)=0\n \n x=0 \ \ or \ \ 4x-3=0 \ \ or \ \ 4x+3 =0\n \nx=0 \ \ or \ \ 4x=3 \ \ / :4 \ \ or \ \ 4x=-3\ \ / :4 \n \n x=0 \ \ or \ \ x=(3)/(4) \ \ or \ \ x=-(3)/(4)
f(x)=16x^4-9x^2\n\nf(x)=0\iff16x^4-9x^2=0\n\nx^2(16x^2-9)=0\iff x^2=0\ \vee\ 16x^2-9=0\n\nx=0\ \vee\ 16x^2=9\n\nx=0\ \vee\ x^2=(9)/(16)\n\nx=0\ \vee\ x=-\sqrt(9)/(16)\ \vee\ x=\sqrt(9)/(16)\n\nx=0\ \vee\ x=-(3)/(4)\ \vee\ x=(3)/(4)

A number divide by 3 algebraic expression

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An algebraic expression is with numbers. 
Set the number as x.
So the expression would be:
x/3

Hope this helps :)

Use the discriminant to determine the number of solutions of the quadratic equation, and whether the solutions are real or complex. Note: It is not necessary to find the roots; just determine the number and types of solutions.2x^2 + x - 1 = 0
4/3x^2 - 2x + 3/4 = 0

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Discriminant is b²-4ac in a quadratic equation Ax²+ Bx+C=0.

If the value of discriminant is less than zero, then the equation has two complex solutions
If the value of the discriminant is equal to zero, then the equation has one solution
If the value of the discriminant is more than zero, then there will be two real solutions.

Just plug in your values and you'll get the right answers.

If the dimensions of a figure are doubled, then the area of the figure is___.

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If the dimensions of a figure are doubled, then the area of the figure is quadrupled.

Answer:

Quadrupled

Step-by-step explanation:

Let us consider rectangle be a figure whose dimensions are a and b.

Then, the area of the rectangle will be:

A=a{*}b

A=ab square units

Now, If we double the dimensions of the rectangle that is 2a and 2b, then the area of the rectangle will become:

A=2a{*}2b

A=4ab square units

Therefore, if we double the dimensions of the rectangle, the area becomes quadrupled.

Thus, If the dimensions of a figure are doubled, then the area of the figure is Quadrupled.