somethingExplanation:
510.17 cm³ is the volume of Iron has a density of 7.86 g/cm3 (1 cm3=1 mL) and has a mass of 4.01 kg.
Density is the amount of mass of a substance present per volume of the cubic centimeter and it is the ratio of the mass of a substance to the volume of the substance with a unit centimeter cube.
The Iron has a density of 7.86 g/cm³ and mass of 4.01 kg so,
mass in gram = 4.10 / 1000 = 0.041
Density = mass/volume
Substituting the value in the equation,
volume = 0.041 /7.86 g/cm³
volume = 510.17 cm³
Therefore, the volume of Iron has a density of 7.86 g/cm3 (1 cm3=1 mL) and has a mass of 4.01 kg is 510.17 cm³.
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635 g
635 g/cm3
634.5 ml
Answer:
JUST B
Explanation:
The mass of 235 cm³ of aluminum, which has a density of 2.70 g/cm³, is calculated to be 634.5 g using the formula Mass = Density × Volume.
To find the mass of a given volume of a substance, you can use the formula: Mass = Density × Volume. In this case, the density of aluminum is given as 2.70 g/cm³ and you need to find the mass of 235 cm³ of aluminum.
Substitute the given values into the formula:
Mass = 2.70 g/cm³ × 235 cm³ = 634.5 g
Therefore, the mass of 235 cm³ of aluminum is 634.5 g.
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18
metallurgy
inductive reasoning
the answer would be:
C. metallurgy
Answer:
93.17 g
Explanation:
Recall that: mol = mass/molar mass
Also; mol = molarity x volume
mole of (NH4)2SO4 to be prepared = 282/1000 (dm3) x 2.50 (mol/dm3)
= 0.705 mol
This can be used to determine the mass of (NH4)2SO4 that will be required.
mass = mole x molar mass
Hence, mass of (NH4)2SO4 required = 0.705 x 132.15
= 93.17 g
Hence, the mass of ammonium sulfate that will be required to prepare 282 mL of a 2.50M solution is 93.17 g