Jamal discovers that the sum of Point B and Point C is zero. A number line with points A, blank, B, blank, 0, blank, C, D, blank. Which sentence is a correct statement about points B and C?
Answers
Answer:
The answer is B.
Step-by-step explanation:
B is two spaces to the left of the 0, and C is two spaces to the right of the the zero meaning B is the opposite of C.
If I am correct please mark me:)
Answer:
b
Step-by-step explanation:
Related Questions
Find an equation of the line that has the given slope and contains the given point. m=7/3 (1,6)
F(-2) =i need help immediately
at a lunch stand, each hamburger has 50 more calories than each order of fries. if 2 hamburgers and 3 orders of fries have a total of 1700 calories, how many calories does a hamburger have?
The sum of six times a number and 8 is equal to five times the number
Answers
√48
=√16*3
=√2^4*3
=2√3
=2 times the 4th root of 3
I hope my answer helped you with your problem. Have a nice day! Feel free to ask more questions.
Answers
Answer:
- 24/24, 1/9, 20/32, 8/8, 3/4
Step-by-step explanation:
Blank 1 = 24/24
- 24/1 = 24, 48/2 = 24
Blank 2 = 1/9
- 3/3 = 1, 27/3 = 9
Blank 3 = 20/32
- 5*4 = 20, 8*4 = 32
Blank 4 = 8/8
- 48/6 = 8, 56/7 = 8
Blank 5 = 3/4
- 21/7 = 3, 28/7 = 4
Answers
Final Answer:
The next number in the sequence is 132.
Solution:
The sequence appears to involve two alternatingoperations:
Start with "six."
Subtract 3: 6 - 3 = 3.
Multiply by 4: 3 * 4 = 12.
Subtract 3: 12 - 3 = 9.
Multiply by 4: 9 * 4 = 36.
Subtract 3: 36 - 3 = 33.
The pattern alternates between subtracting 3 and then multiplying by 4. To find the next number:
Multiply 33 by 4: 33 * 4 = 132.
So, the next number in the sequence is 132.
Learn more about sequence here:
#SPJ11
Answer: The answer is 132
Step-by-step explanation: In each number in the sequence it switches between -3 or x4.
The number before just did -3 so you should have to multiply 33 by 4 which is 132.
I also checked it
Answers
Answer:
-3/2
Step-by-step explanation:
formula of slope (y2-y1/x2-x1)
Answers
Answer:
The answer is 16%
Step-by-step explanation:
use the percent error formula.
in this problem,
e= 75
t=90
substitute and solve.
16%
we are dealing with percents so rounding to nearest whole number will suffice.
hope this helps!
Answers
Answer:
In conclusion, the only possible outcome is $61^\circ,$ $61^\circ,$ $61^\circ,$ $178^\circ,$ and $179^\circ$.
Step-by-step explanation:
Okay, so let's just dive in head on. Since we know that all the angles in a pentagon must add up to $540^{\circ}$ and that there are $5$ angles in a pentagon, we know that $61^\circ$ is the third angle, $c$, of the pentagon. We also know that $a^\circ,$ $b^\circ,$ $c^\circ,$ $d^\circ,$ and $e^\circ,$ are all less than $180$. We know that in a regular pentagon all angles are $108^\circ$, however, the median angle is $61^\circ$ so we know that this is not a regular pentagon.
Now, since the median of our pentagon is $61^\circ$, the other numbers would center around $61$. With this information, we can figure out many solutions. However, there is one very important piece of information we almost forgot- the mode! What this means is, you cannot have an answer like $60^\circ,$ $61^\circ,$ $61^\circ,$ $179^\circ,$ and $179^\circ$ since there is only one mode.
Now let's figure out what the mode is. Is it $61$, or is it another number? Let's explore the possibilities of the mode being $61.$ If the mode is $61,$ it could either be $b$ or $d$. Let's first think about it being $b$. This would mean that the data set is $a^\circ,$ $61^\circ,$ $61^\circ,$ $d^\circ,$ and $e^\circ.$ The numbers would still need to add up to $540,$ so let's subtract $122$ (the two $61$'s) from $540$ to see how many more degrees we still need. We would get $418$. This means that $a,$ $d,$ and $e$ added together is $418$. If it is true that $b$ is $61,$ this would mean that $a, \leq61, 61, d, \leq e.$ If this is true, there could only be one possibility. This would be $61^\circ,$ $61^\circ,$ $61^\circ,$ $178^\circ,$ and $179^\circ$. If we changed $a$ to $60$, then there would be two modes. $a$ can't be $59$ since then $e$ would be $180$. $a$ also can't be any higher than $61$ since then it would not be $a$ at all. So basically, if $b$ were $61$, then the data set could only be $61^\circ,$ $61^\circ,$ $61^\circ,$ $178^\circ,$ and $179^\circ$.
But what if $d$ were $61?$ Then the data set would be $a, \leq b, 61, 61, \leq e.$ It would not be possible. This is because the highest number $e$ can be is $179.$. If this is, then we still have $239^\circ$ left to go. $a$ and $b$ would have to be greater than $61$, and this would not be possible because then it would not be $a$ and $b$ at all.
Okay, we're almost done. What if the mode isn't $61$ at all, but a whole different number? This would either mean that $a=b$ or that $d=e$. If $d=e$ and $d=179,$ this means that $a$ and $b$ would have to both be $60.5$. We can't have two modes, and $b$ could not be $61$ because we can't have two modes. If $d$ were smaller, like $178$, then $a+b$ would need to be $123$ and this is not possible since that would be over the median of $61$. $d$ cannot be larger since that would go over the max of $179$.
If $a=b$, let's think about if $a$ were $60$. $d+e$ would need to equal 359, and once again we can't have two modes, and $d$ could not be $179$ because $e$ cannot be $180$. If $a$ were smaller, like $59$, then $d+e$ would need to be $361$ and this is not possible since that would be over the max of $179$. $a$ cannot be larger since that would exceed the median of $61$.
In conclusion, the only possible outcome is $61^\circ,$ $61^\circ,$ $61^\circ,$ $178^\circ,$ and $179^\circ$.
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