Answer:15
8-(-7)=8+ 7=15 BECAUSE -(-7) = +7
Step-by-step explanation:
BECAUSE -(-7) = +7 SO THE PROBLEM CHANGES TO 8+7=15
P=10 HAS NOTHING TO DO WITH THE FORMULA. K-M=?
Algorithm to find the cheapest route to visit each city and return home again to Athens.
Answer:
the answer is Athens-Buford-Cu-Dacul-Athens
Step-by-step explanation:
Answer:
14= 1, 2, 7, 14
6= 1, 2, 3, 6
Answer:
The mean speed of the automobiles traveling on this road is the closest to 65 mph.
Step-by-step explanation:
frequency distribution of speeds.
Speed (mph) | Frequency
45 up to 55 | 70
55 up to 65 | 360
65 up to 75 | 250
75 up to 85 | 110
Using the midpoint method, we represent each group/class of speeds with the midpoint speed, then go ahead to compute the mean.
Let the speed be x
The frequency be f
x | f
50 | 70
60 | 360
70 | 250
80 | 110
Mean = (Σfx)/(Σf)
Σfx = (50×70) + (60×360) + (70×250) + (80×110) = 51,400
Σf = 70 + 360 + 250 + 110 = 790
Mean = (Σfx)/(Σf)
Mean = (51400/790) = 65.06 mph ≈ 65 mph
The mean speed of the automobiles traveling on this road is the closest to 65 mph
Hope this Helps!!!
Answer:
27.76% probability that a randomly selected bag of this size has 10 or more green candies
Step-by-step explanation:
I am going to use the normal approximation to the binomial to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
The standard deviation of the binomial distribution is:
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that , .
In this problem, we have that:
So
What is the probability that a randomly selected bag of this size has 10 or more green candies
Using continuity correction, this is , which is 1 subtracted by the pvalue of Z when X = 9.5. So
has a pvalue of 0.7224
1 - 0.7224 = 0.2776
27.76% probability that a randomly selected bag of this size has 10 or more green candies
Answer:
Step-by-step explanation:
The number x of green candies in a bag of 40 candies follows a binomial distribution, because we have:
So, the probability that in a bag of 40 candies, x are green is calculated as:
Replacing, n by 40 and p by 0.2, we get:
So, the probability that a randomly selected bag of this size has 10 or more green candies is equal to:
Where
So, we can calculated P(0) and P(1) as:
At the same way, we can calculated P(2), P(3), P(4), P(5), P(6), P(7), P(8) and P(9) and get that P(x<10) is equal to:
Finally, the probability that a randomly selected bag of this size has 10 or more green candies is:
A. A is a function of B and B is a function of A
B. A is a function of B
C B is a function of A
D. Neither is a function of the other
The number of reps Tobias does depends on the day, thus 'A' is a function of 'B'. The number of reps in itself does not determine the day, so 'B' cannot be a function of 'A'. The correct answer is 'A is a function of B'
In this situation, each day Tobias lifts weights, he carries out a certain number of reps. So, the number of reps (A) he does is dependent on the day (B), hence, A is a function of B. It simply means that for every day (input), there's a corresponding number of reps (output). It is not necessarily true that for each specific number of reps, there is a specific day. Hence, B cannot be said to be a function of A. Therefore, the correct answer is 'A is a function of B'.
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