(2^8 ⋅ 5^−5 ⋅ 19^0)−2 ⋅ 5 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 ⋅ 2^28
Write your answer in simplest form. Show all of your steps
(2^8 . 5^-5 . 19^0)^-2
using PEMDAS
this = (2^8 * 1/5^5 * 1)^-2
= (5^5 / 2^8)^2
= 5^10 / 2^16
mark me brainlest pls thxs
Answer:
The area of her friend's town
Step-by-step explanation:
Given : Jada lives in a city that has an area of 344.6 square miles.
Her friend lives in a town that is one-tenth, or 0.1, that size.
To find : The area of her friend's town.
Solution : The area of Jada house = 344.6 square miles.
Her friends house is one-tenth or 0.1 of 344.6 square miles.
Actual area of her friend's house is = 0.1 of Area of Jada house
Therefore, The area of her friend's town
Given the scenario, no valid integer input would result in an output of $3 from Dorothy's ? button on her calculator. The three conditions specified do not match any integer when the output is $3.
Given that the output of the ? button on Dorothy's calculator is $3, one thing that could have been input and fit one of the conditions is 4, because when an integer is divisible by 4, the calculator outputs its one-fourth. Since 4 is divisible by 4 and one-fourth of 4 equals 1, that's not correct. Now let's check the condition for even numbers not divisible by 4. The calculator outputs 1 more than half the number. So, if we plug in $3 as the output and solve the equation, we get: 3 = 1 + 1/2 (input). Solving for the input, we get 2*2 = 4, which is still wrong. So, finally, we check the condition for odd numbers. Here, the calculator outputs 1 less than triple the input. Substituting $3 as the output, we solve for the input: 3 = 3*(input) - 1. Solving for input, we get input = 4/3, which is not an integer. Therefore, there could not have been an integer input that resulted in a $3 output in this case.
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