Answer-
The coordinates of D' are (-1, -5)
Solution-
The coordinates of D are (-1, 5).
While reflecting any points across the x-axis with coordinates as (x, y) becomes, (x, -y). i.e sign of y-coordinate changes.
The rule is (x, y) → (x, -y)
Applying so, after reflecting point D, its reflection D' will have coordinates as (-1, -5)
Therefore, the y-coordinate is -5.
The answers are A and B, -5 and -1. Hope this helps!
Answer:
Hey!
The 6th term of your sequence is 23!
Step-by-step explanation:
This is how you get it...
1) T6=3n+5 (the 6th term and the equation...)
2. We now do T6=3(6)+5 (3 x 6 then add 5)
3. In other words... T6=18+5
4. We work it out 18 + 5 = 23
HOPE THIS HELPS!!
2+x y
if y is a non zero constant, which equation represents the value of x in the given equation?
A) x=3y-2
B)x=3y+2
C)x=9y-6
D)x=9y+6
I have no idea how to solve.
Answer:
m = 46 - n
Good luck
Answer:
( m, n) = ( -6 , 11) .
Step-by-step explanation:
Given : A system of equations is shown below: n = 3m + 7
n − 2m = 1.
To find : What is the solution, in the form (m, n), to the system of equations.
Solution : We have given
n = 3m + 7 ------(1)
n − 2m = 1
We can write it as n = 1 + 2m -----(2)
In equating both equation (1) = (2).
n = n
3m + 7 = 1 +2m.
On subtracting both sides by 2m
3m - 2m + 7 = 1.
m + 7 = 1
On subtracting by 7 both sides
m = 1 - 7.
m = -6.
On plugging the value of m = -6 in equation 1.
n = 3m + 7
n = 3 (-6) + 7.
n = -18 + 7.
n = -11.
Then solution ( m, n) = ( -6 , 11) .
Therefore, ( m, n) = ( -6 , 11) .
Answer-
The line equation is,
Solution-
The line meets x-axis at the point M, i.e M is the x-intercept of this line. At the x-intercept y=0, so
So, coordinate of M is
The line meets y-axis at point N, i.e N is the y-intercept of this line. At the y-intercept x=0, so
So, coordinate of N is
The line joining M and N can be found out by applying two point formula of straight line,
As it is given that all the coefficients are integers, so multiplying with 3
Solution: As given line y =3x-5 meet x-axis at the point M.
On x axis y coordinate is zero.
Put y =0 in above equation, we get →x = 5/3
∴ Coordinate of M is (5/3,0).
As, also given , line 3y+2x=2 meets y-axis at point N.
On y axis , x coordinate is zero.
Substituting , x=0 in above equation, gives y =2/3.
Coordinate of point N is (0,2/3).
Equation of line passing through two points (a,b) and (p,q) is given by
→
Or as X intercept = 5/3, and Y intercept = 2/3
Equation of line in intercept form is →, where a and b is X intercept and y intercept respectively.
So, line passing through (5/3,0) and (0,2/3) is given by
→
→
→ 6 x + 15 y =10 [Taking LCM of 5 and 2 which is 10]
→ 6 x + 15 y -10=0, which is equation of the line joining M and N in the form ax + by + c = 0 where: a,b,c are integers.