Point D(−1, 5) is reflected across the x-axis.Which statements about D' are true?

Select each correct answer.

The y-coordinate is−5.

The x-coordinate is −1.

The y-coordinate is 5.

The x-coordinate is 1.

Answers

Answer 1
Answer:

Answer-

The coordinates of D' are (-1, -5)

Solution-

The coordinates of D are (-1, 5).

While reflecting any points across the x-axis with coordinates as (x, y) becomes, (x, -y). i.e sign of y-coordinate changes.

The rule is (x, y) → (x, -y)

Applying so, after reflecting point D, its reflection D' will have coordinates as (-1, -5)

Therefore, the y-coordinate is -5.


Answer 2
Answer:

The answers are A and B, -5 and -1. Hope this helps!


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The nth term of a sequence is 3n+5 to the 6th terms sequence

Answers

Answer:

Hey!

The 6th term of your sequence is 23!

Step-by-step explanation:

This is how you get it...

1) T6=3n+5  (the 6th term and the equation...)

2. We now do T6=3(6)+5  (3 x 6 then add 5)

3. In other words... T6=18+5

4. We work it out 18 + 5 = 23

HOPE THIS HELPS!!

30 former classmates gathered to celebrate the anniversary of their school graduation. Each of them greeted and shook hands with every other without any exceptions how many handshakes were exchanged when everyone was finished?Note: When person A shakes with person B, person B is also shaking with person A. It is counted as one handshake.

Answers

Let's pick one person at random and call it the 'first'.

That person shakes hands with 29 other classmates.

Take another person different from the first, we'll call him the 'second'. Since he has already shaken hands with the first, he shakes hands with 28 other classmates.

The 'third' person will likewise shake hands with 27 other classmates, and so on.

Hence, the total number of handshakes is 29+28+27+...+2+1 = 29*30/2=435 handshakes

The answer is 435 handshakes when everyone was finished. I hope this is correct.

1-4x = 3-4y___ ____
2+x y

if y is a non zero constant, which equation represents the value of x in the given equation?
A) x=3y-2
B)x=3y+2
C)x=9y-6
D)x=9y+6

I have no idea how to solve.

Answers

the answer is A
x=3y-2
see photo attached

Translate to algebraic expression.Justin had $46 before spending n dollars on jeans. How much money remains?

Answers

Answer:

m = 46 - n

Good luck

A system of equations is shown below: n = 3m + 7 n − 2m = 1 What is the solution, in the form (m, n), to the system of equations? (3, 7) (1, 8) (−3, −2) (−6, −11)

Answers

Answer:

( m, n) = ( -6 , 11) .

Step-by-step explanation:

Given  : A system of equations is shown below: n = 3m + 7

n − 2m = 1.

To find :  What is the solution, in the form (m, n), to the system of equations.

Solution : We have given

n = 3m + 7 ------(1)

n − 2m = 1

We can write it as   n = 1 + 2m -----(2)

In equating both equation (1) = (2).

n = n

3m + 7  = 1 +2m.

On  subtracting both sides by 2m

3m -  2m + 7 = 1.

m + 7 = 1

On subtracting by 7 both sides

m = 1 - 7.

m = -6.

On plugging the value of m = -6 in equation 1.

n = 3m + 7

n = 3 (-6) + 7.

n = -18 + 7.

n = -11.

Then solution ( m, n) = ( -6 , 11) .

Therefore, ( m, n) = ( -6 , 11) .

n=3 m+7
n-2 m=1     | -2 m      => n=1+2m

n=3 m+7
n=1+2 m

n=n

3m+7=1+2m       |-7 and -2m
m = -6

n=1+2m 
n=1+2*(-6)
n=-11

(-6,-11)

The line y =3x-5 meet x-axis at the point M. The line 3y+2x=2 meets y-axis at point N. Find the equation of the line joining M and N in the form ax + by + c = 0 where: a,b,c are integers.

Answers

Answer-

The line equation is,

\boxed{\boxed{6x+15y-10=0}}

Solution-

The line y =3x-5 meets x-axis at the point M, i.e M is the x-intercept of this line. At the x-intercept y=0, so

\Rightarrow 0 =3x-5

\Rightarrow 3x=5

\Rightarrow x=(5)/(3)

So, coordinate of M is ((5)/(3),\ 0)

The line 3y+2x=2 meets y-axis at point N, i.e N is the y-intercept of this line. At the y-intercept x=0, so

\Rightarrow 3y+2(0)=2

\Rightarrow 3y=2

\Rightarrow y=(2)/(3)

So, coordinate of N is (0,\ (2)/(3))

The line joining M and N can be found out by applying two point formula of straight line,

\Rightarrow (y-y_1)/(y_2-y_1)=(x-x_1)/(x_2-x_1)

\Rightarrow (y-0)/((2)/(3)-0)=(x-(5)/(3))/(0-(5)/(3))

\Rightarrow (y)/((2)/(3))=(x-(5)/(3))/(-(5)/(3))

\Rightarrow -(5)/(3)y=(2)/(3)(x-(5)/(3))

\Rightarrow -5y=2(x-(5)/(3))

\Rightarrow -5y=2x-(10)/(3)

\Rightarrow 2x+5y-(10)/(3)=0

As it is given that all the coefficients are integers, so multiplying with 3

\Rightarrow 6x+15y-10=0

Solution: As given  line y =3x-5 meet x-axis at the point M.

  On x axis y coordinate is zero.

Put y =0 in above equation, we get →x = 5/3

∴ Coordinate of M is (5/3,0).

As, also given , line 3y+2x=2 meets y-axis at point N.

On y axis , x coordinate is zero.

Substituting , x=0 in above equation, gives y =2/3.

Coordinate of point N is (0,2/3).

Equation of line passing through two points (a,b) and (p,q) is given  by

       → (y-b)/(x-a) =(q-b)/(p-a)

Or as X intercept = 5/3, and Y intercept = 2/3

Equation of line in intercept form is →(x)/(a) + (y)/(b) =1, where a and b is X intercept and y intercept respectively.

So, line passing through (5/3,0) and (0,2/3) is given by

(x)/((5)/(3))  +  (y)/((2)/(3))=1

 → (3x)/(5) + (3y)/(2) =1  

→ 6 x + 15 y =10 [Taking LCM of 5 and 2 which is 10]

6 x + 15 y -10=0, which is equation of the line joining M and N in the form ax + by + c = 0 where: a,b,c are integers.