Carlita saw 5 times as many robins as cardinals while bird watching. She saw a total of 25 birds. How many more robins did she than cardinals?

Answers

Answer 1

Answer: Carlita was either sipping the hot chocolate while she was out, or else
approximating the numbers. The exact number she reported is not
possible. To see why, I'll do it strictly by the math:

Robins = 5 times
Cardinals = 1 time

Total birds = 6 times

6 times = 25 birds

Divide each side by 6 : 1 time = 25/6 = 4-1/6 birds

Robins = 5 times = 20-5/6 of them
Cardinals = 1 time = 4-1/6 of them

Total: (20-5/6) + (4-1/6) = 25 birds.

How many more robins than cardinals = (20-5/6) - (4-1/6) = 16-2/3 more.

The math works out fine. But if the numbers she reported are true,
then some of what she saw was partial birds ... legs, or feathers,
things like that. Eeeew. I don't want to talk about it.

Answer 2

Answer: 20 because 5x5=25 so she saw 5 x as many if you divide 5 and 25 you get five

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Solve for x 64^x-2=256^2x

Answers

$64^(x-2)=256^(2x)\n \n(4^3)^(x-2)=(4^4)^(2x)\n \n4^(3x-6)=4^(8x)\ \ \ \ \Leftrightarrow\ \ \ \ 3x-6=8x\n\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3x-8x=6\n\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -5x=6\ \ \ \ \Leftrightarrow\ \ \ \ x=- (6)/(5)$

Power set of {e,f,m,n,o}

Answers

$\{\emptyset,\{e\},\{f\},\{m\},\{n\},\{o\},\{e,f\},\{e,m\},\{e,n\},\{e,o\},\{f,m\},\{f,n\},\n \{f,o\},\{m,n\},\{m,o\},\{n,o\},\{e,f,m\},\{e,f,n\},\{e,f,o\},\{e,m,n\},\n \{e,m,o\},\{e,n,o\},\{f,m,n\},\{f,m,o\},\{f,n,o\},\{m,n,o\},\{e,f,m,n\},\n \{e,f,m,o\},\{e,f,n,o\},\{e,m,n,o\},\{f,m,n,o\},\{e,f,m,n,o\}\}$

$n=5\ \ \ \Rightarrow\ \ \ 2^n=2^5=32\n\n$

$\emptyset;\n\{e\},\{f\},\{m\},\{n\},\{o\};\n\{e,f\},\{e,m\},\{e,n\},\{e,o\},\{f,m\},\{f,n\},\{f,o\},\{m,n\},\{m,o\},\{n,o\};\n\{e,f,m\},\{e,f,n\},\{e,f,o\},\{e,m,n\},\{e,m,o\},\{e,n,o\},\{f,m,n\},\n\{f,n,o\},\{f,m,o\},\{m,n,o\};\n\{e,f,m,n\},\{e,f,m,o\},\{e,f,n,o\},\{e,m,n,o\},\{f,m,n,o\};\n\{e,f,m,n,o\}$

The length of x 200 feet

Answers

Answer:

If the length of x is less than 200, then add <.

If the length of x is more than 200, then add >.

If the length of x is 200, then add =.

Step-by-step explanation:

Find the value of k such that (k, k) is equidistant from (−2, 0) and (0, 5). k =____

Answers

To find the value of k such that (k, k) is equidistant from (-2, 0) and (0, 5), we can use the distance formula.

The distance between two points (x1, y1) and (x2, y2) is given by the formula:

Distance = √((x2 - x1)² + (y2 - y1)²)

Let's calculate the distances from (k, k) to (-2, 0) and (0, 5) and set them equal to each other:

√((k - (-2))² + (k - 0)²) = √((k - 0)² + (k - 5)²)

Simplifying this equation:

√((k + 2)² + k²) = √(k² + (k - 5)²)

Squaring both sides of the equation to eliminate the square roots:

(k + 2)² + k² = k² + (k - 5)²

Expanding and simplifying:

k² + 4k + 4 + k² = k² + k² - 10k + 25

2k² + 4k + 4 = 2k² - 10k + 25

Rearranging terms:

4k + 4 = -10k + 25

Combining like terms:

14k = 21

Dividing both sides by 14:

k = 21 / 14

Simplifying the fraction:

k = 3 / 2

Therefore, the value of k that makes (k, k) equidistant from (-2, 0) and (0, 5) is k = 3/2.

janelle practices basketball every afternoon in driveway.Each day,her goal is to make 4 more baskets than she made the day before. if she makes 10 baskets the first day and meets her goal for 2 weeks,howmany baskets will janelle make on the 14th day?

Answers

In the given question, there are several information's worth noting. Based on these given information's the actual answer to the question can be found. She makes 10 baskets on the first day and then increases the number of baskets by 4 on every consecutive days. So the thing that needs to be found is the number of baskets he makes on the 14th day. This is an arithmetic progression problem.
Now if we consider the 14th day as the Nth term, then we can write the equation as
A(N) = 4(N - 1) + 10
A(14) = 4(14 - 1) + 10
A(14) = (4 * 13) + 10
= 52 + 10
= 62
So Janelle will make 62 baskets on the 14th day.

Last year Mr. John Q. Public received an inheritance. He paid $20\%$ in federal taxes on the inheritance, and paid $10\%$ of what he had left in state taxes. He paid a total of $\$10{,}500$ for both taxes. How many dollars was the inheritance?

Answers

Answer:

37,500

Step-by-step explanation:

0.2x+0.1(x−0.2x)=105000.2x+0.1(x−0.2x)=10500

0.3x−150x=105000.3x−150x=10500

15x−x50=1050015x−x50=10500

x=10500∗5014=1500∗25=37500

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