PHYSICS HIGH SCHOOL

2a. Abecomes
jeep starts from it the
starts from it the state of rest. If its
velocity 60m/s and its take 5 minute: what is the accelera
ution of the jeep
the distanced travelled by
the jeep:

Answers

Answer 1

Answer:

$\bf \underline{ \underline{Given : }}$

Initial velocity,u = 0 m/s

Final velocity,v = 60 m/s

Time taken,t = 5 min = 5 × 60 sec = 300 seconds

$\bf \underline{ \underline{</p><p>To \: be \: calculated : }}$

Calculate the acceleration ( a ) and distance (s ) covered by the jeep.

$\bf \underline{ \underline{Solution : }}$

We will first calculate the acceleration of the jeep.

CASE 1 :

By Using first equation of motion ,

$\sf \: v = u + at$

$\sf \star \: Substituting \: the \: values...$

$\sf\rightarrow \: 60 = 0 + a * 300$

$\sf \rightarrow \: 60 = 300a$

$\sf \rightarrow \: 300a = 60$

$\sf \rightarrow \: a = \cancel (300)/(6)$

$\sf \rightarrow \: a = 50 \: m {s}^( - 2)$

Thus,the acceleration of the jeep is 50 m/s².

Now, Let us calculate the distance travelled by the jeep.

CASE 2 :

By Using third equation of motion ,

$\sf {v}^(2) = {u}^(2) + 2as$

$\sf \star \: Substituting \: the \: values...$

$\sf \rightarrow \: {60}^(2) = {0}^(2) + 2 * 50 * s$

$\sf \rightarrow \: 3600 = 100s$

$\sf \rightarrow \: 100s = 3600$

$\sf \rightarrow \: s = \cancel(3600)/(100)$

$\sf \rightarrow \: s = 36 \: m$

Thus,the distance covered by the jeep is 36 m .

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a bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

Answers

The expression for the bullet's speed vbullet is $v=\sqrt{(2\mu_k (m+M)gd)/(m)}$ and the speed of a 9.0 g bullet is v=16.8 m/s

Explanation:

A bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d across a horizontal surface. the coefficient of kinetic friction is μk.

The initial kinetic energy of the bullet is given by

$K_i = (1)/(2)mv^2$

where

m is the mass of the bullet

v is the initial speed of the bullet

The expression for the bullet's speed vbullet is

$F=\mu_k (m+M) g$

where

$\mu_k$ is the coefficient of kinetic friction

g is the acceleration of gravity

The work done by the force of friction is

$W=-Fd = -\mu_k (m+M)g d$

where d is the displacement of the block+bullet.

Because the final kinetic energy is zero (the bullet with the block comes at rest), we can write:

$W=K_f - K_i = -K_i$

And so

$-\mu_k (m+M) g d = -(1)/(2)mv^2$

By solving for v, the solution for the bullet speed:

$-\mu_k (m+M) g d = -(1)/(2)mv^2\nv=\sqrt{(2\mu_k (m+M)gd)/(m)}$

The speed of a 9.0 g bullet that, when fired into a 12 kg stationary wood block causes the block to slide 5.4 cm across a wood table. Assume that k=0.20.

We have:

the mass of the bullet, m = 9.0 g = 0.009 kg

the mass of the block, M = 12 kg

the distance covered by the block+bullet, d = 5.4 cm = 0.054 m

the coefficient of friction, $\mu_k = 0.20$

the acceleration of gravity, $g = 9.8 m/s^2$

By substituting, we got

$v=\sqrt{(2 (0.20) (0.009 kg+12 kg)(9.8 m/s^2)(0.054 m))/(0.009 kg)}=16.8 m/s$

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uk=2m*the normal force
the distance d is needed only if you were asked about work

Two shoes each have a mass of 0.1 kg. if the are .15m apart what is the gravitational force between them? G = 6.67 x 10^-11 N (m/kg)^2

Answers

Formula:

$F = G \cdot (m_1 m_2)/(r^2)$

m1, m2 - mass in kg
r - distance in meter.

m1 = m2 = 0.1kg
r = 15m

$F = 6.67 \cdot 10^(-11) N \cdot (m^2)/(kg^2) \cdot (0.1 \cdot 0.1 kg^2)/(15^2 m^2) \n \n F=(6.67 \cdot 0.01 \cdot 10^(-11))/(225) N \n \n F \approx 0.00002964 \cdot 10^(-11) N \n \n F \approx 2.96 \cdot 10^(-16) N$

Greetining

Answer:

the answer is =2.96 x10^-11 N

Explanation:

Q2. Zara travelled in a train moving at an average speed of 120km/h and covered a distance of 40km towards East. Calculate the time taken by the train to cover this distance.

Answers

Answer: 20 minutes

Explanation:

Given the following :

Average speed of train = 120km/hr

Distance = 40km.

The time take by the train moving at an average speed of 120km/hr to cover a distance of 40km due is ;

Recall:

Speed = distance / time

Therefore,

Time taken = distance covered / speed

Time taken = 40km / 120km/hr

Time taken = 1/ 3 hr

Therefore, 1/3 rd of an hour equals

1/3 × 60 = 20 minutes.

Time taken) 20 minutes

Time taken by tain to cover distance is 20 minutes as:

Distance= 40 km

Speed= 120 km/h

Time= distance/speed

= 40/120

= 1/3 hour

= 20 min

or =0.33 hrs

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Draw a diagram to show how two resistors R1 and R2 are connected in parallel.

Answers

See attached
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Answers

The swimming pool at perris hill plunge is 50 feet long and 25 feet wide. if the bottom of the pool is slanted so that the water depth is 3 feet at the shallow end and 15 feet at the deep end,the angle of elevation at the bottom of the pool is calculated by Over a 50 foot (surface) length, there is a 12 foot (vertical) drop. tan A = 12/50 = 0.24 A = 13.5 degrees

Archimedes' principle states that the buoyant force on an object is equal to the density of the fluid it displaces.

Answers

The buoyant force on an object submerged in a fluid is equal to the density of the fluid it displaces.

According to Archimedes' principle, the magnitude of the buoyant force is equal to the weight of the fluid displaced by the object. The weight of the displaced fluid is directly proportional to the volume of the fluid displaced and the density of the fluid. So, the buoyant force (B) can be mathematically represented as:

B = ρ * V * g

Where:

ρ (rho) is the density of the fluid,

V is the volume of the fluid displaced by the object, and

g is the acceleration due to gravity.

The key point to remember is that the buoyant force acts in the opposite direction to gravity. If the object's weight is less than the buoyant force, it will float; if it is greater, it will sink.

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True apex...................

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