Find the zeros of the function g(x) = 4x^2 - 484

Answers

Answer 1

Answer:

There are two zeros of the function g(x) that is 11 , -11

What are zeros of the function?

The zero of a function is any replacement for the variable that will produce an answer of zero. Graphically, the real zero of a function is where the graph of the function crosses the x‐axis; that is, the real zero of a function is the x‐intercept(s) of the graph of the function.

According to the question

g(x) = $4x^(2)$ - 484

To find the zeros of a function, find the values of x where g(x) = 0.

Therefore,

0 = $4x^(2)$ - 484

0 = $x^(2) - 121$

0= $(x-11)(x+11)$

i.e ,

$x = 11 ,-11$

Hence , there are 2 zeros of the function g(x) that is 11 , -11 .

To know more about zeros of the function here :

brainly.com/question/22101211

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Answer 2

Answer:

Answer:

Step-by-step explanation:

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What is the answer M divided by 3+5=2

Answers

Solve for M by simplifying both sides of the equation, then isolating the variable.M=−9

Help on logarithmic equation

Answers

$\log _( 2 ){ \left( 3-x \right) } +\log _( 2 ){ 5 } =2\log _( 3 ){ 5 } \n \n \log _( 2 ){ \left( 5\left( 3-x \right) \right) } =\log _( 3 ){ \left( { 5 }^( 2 ) \right) } \n \n { 2 }^{ \log _( 3 ){ 25 } }=5\left( 3-x \right) \n \n { 2 }^{ \log _( 3 ){ 25 } }=15-5x\n \n 5x=15-{ 2 }^{ \log _( 3 ){ 25 } }\n \n x=\frac { 15 }{ 5 } -\frac { { 2 }^{ \log _( 3 ){ 25 } } }{ 5 } \n \n x=3-\frac { { 2 }^{ \log _( 3 ){ 25 } } }{ 5 }$

B1 of a trapezoid in which Area = (48x+68) inch squared, Height = 8 in, B2 = (9x + 12) in.what I have so far is

48x +68 = 8 (B1 + 9x +12)

what do I do from there????????????????? the question is asking to solve for Base 1/ B1

Answers

A=(1/2)(b1+b2)h =

=(48x+68)in² = (1/2)( b1+(9x+12))8

=b1= 3x+5

Write two statements that show the relationship between the values of the numbers 0.5 and 0.05

Answers

1. The value of 0.5 is ten times greater than the value of 0.05.

2. The value of 0.05 is one-tenth of the value of 0.5.

Which expression is eqivalent to (x^2-3x)(4x^2+2x-9)

Answers

For this case we must find an expression equivalent to:

$(x ^ 2-3x) (4x ^ 2 + 2x-9) =$

We apply distributive property, term by term, taking into account that: $- * + = -\n- * - = +\nx ^ 2 * 4x ^ 2 + x ^ 2 * 2x-x ^ 2 * 9-3x * 4x ^ 2-3x * 2x + 3x * 9 =$