It's weight would be: x*150 / 100
Where, x= weight of nickel
A nickel weighs 5 grams. As a dime is said to weigh 50% as much as a nickel, we calculate 50% of 5 to find the weight of the dime, which gives us 2.5 grams.
The subject of this question is in the context of Mathematics, more specifically proportional relationships. The weight of a nickel is 5 grams. As mentioned, a dime weighs 50% less than a nickel. So to find the weight of the dime, we calculate 50% of 5 grams.
First, to find 50%, we need to divide by 100 and then multiply by 50. That is: (5 / 100) * 50 = 2.5 .
So, a dime weighs 2.5 grams. Always remember, weight measurements can have slight variations depending upon measurement techniques and tools used. For instance, if you place a coin on a standard electronic balance, you may obtain a weight of 2.5 g with a nominal uncertainty in the measurement of ± 0.01 gram. However, in a general sense for our calculation with given data, the weight of a dime is indeed 2.5 grams.
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Answer:
The correct method is **c) Jaleel is correct because 2(x - 2) equals 2x - 2.**
Here's why:
Jaleel's method correctly expands the expression 2(x - 2)^2. When you square (x - 2), you get (x - 2)(x - 2), which simplifies to x^2 - 4x + 4. Then, multiplying this by 2 gives you 2(x^2 - 4x + 4), which simplifies further to 2x^2 - 8x + 8.
Lisa's method, on the other hand, incorrectly simplifies it as 2x. This is not the correct expansion of 2(x - 2)^2, as it neglects the square of (x - 2) and simplifies it incorrectly.
So, Jaleel's method is the correct one.
Answer:The correct answer is B:2,154
Step-by-step explanation: