Answer:
Step-by-step explanation:
The formula for finding the combination of two given positive numbers is given by
Where n and r are positive numbers
From the question we have
5 C 3
Simplify
That's
We have the final answer as
Hope this helps you
Divide 1/5 and 3/5
Answer:
3/5
Step-by-step explanation:
You divide 1 and 3. Keep the denominator since it is the same number
Hope this was helpful, Have a Great Day!!
Answer:
1/3
Step-by-step explanation:
1/5 multiplied by 3/5 = 15/5 = 3
then flip over and put 1/3
The formula becomes w = (200P - 20)/3.
Given: Formula
P = (3w + 20)/200
Now, we will convert this in the form of P.
⇒ P = (3w + 20)/200
multiply both sides by 200, we get:
⇒ 200 P = 3w + 20
⇒ 200P - 20 = 3w
⇒ w = (200P - 20)/3
Therefore, the formula after making w as the subject becomes:
w = (200P - 20)/3
Learn more about the Equivalent Equations here: brainly.com/question/4348710
#SPJ2
Answer:
Step-by-step explanation:
I assume the correct formula is
P = (3w + 20)/200
Solve for w.
200P = 3w + 20
200P - 20 = 3w
(200P - 20)/3 = w
To find the probability that exactly n cards are dealt before the first ace appears, we can use the concept of a geometric distribution. In a geometric distribution, we're interested in the number of trials (in this case, card draws) required for a success to occur (in this case, drawing an ace) for the first time.
The probability of drawing an ace in a single draw from a well-shuffled pack of 52 cards is 4/52 because there are 4 aces out of 52 cards.
So, the probability of drawing a non-ace in a single draw is (52 - 4)/52 = 48/52.
Now, let X be the random variable representing the number of cards drawn before the first ace appears. X follows a geometric distribution with parameter p, where p is the probability of success on a single trial.
P(X = n) = (1 - p)^(n - 1) * p
In this case, p is the probability of drawing an ace on a single trial, which is 4/52, and n is the number of cards drawn before the first ace.
So, the probability that exactly n cards are dealt before the first ace appears is:
P(X = n) = (1 - 4/52)^(n - 1) * (4/52)
Now, to find the probability that exactly k cards are dealt in all before the second ace appears, we need to consider two scenarios:
1. The first ace appears on the nth card, and the second ace appears on the kth card after that. This is represented by P(X = n) * P(X = k).
2. The first ace appears on the kth card, and the second ace appears on the nth card after that. This is represented by P(X = k) * P(X = n).
So, the total probability that exactly k cards are dealt before the second ace appears is:
P(X = n) * P(X = k) + P(X = k) * P(X = n)
You can calculate this probability using the formula for the geometric distribution with p = 4/52 as mentioned earlier for both P(X = n) and P(X = k).
Number of Ounces. Number of Cups
16. 3.6
10. 2.3
8. 1.8
The number of possible batting lineups is 720
Explanation
Total number of players in the team = 9
The center fielder must bat fourth, the second baseman must bat third and the pitcher last. That means, 3 slots in the batting line-up are already assigned to 3 players.
So, the remaining (9 - 3) = 6 players will be assigned to remaining 6 slots.
Thus, the possible number of ways so that 6 players can be assigned to 6 slots will be: