Answer:
C: water crops often to wet soil.
Explanation:
Working in the plan industry, it becomes obvious that when watering the plants often, it will pack down the topsoil into the plant. Topsoil is lose at first as stated above, but when enough water gets on it, it becomes almost like mud. This is the kind of topsoil you want. No wind or water will mess it up because it already it watered! It will also help the grow. In addition, plowing is not correct because you only need to plow twice in the plant process. Before you plant the seeds, and to harvest the crops. If you plow to soon and often, you won’t have any plants.
electron levels
orbits
energy levels
Answer:
Density is increased
Explanation:
I took a test and that was the correct answer :)
To solve this we assume that the gas is an ideal gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At a constant temperature and number of moles of the gas the product of PV is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:
P1V1 =P2V2
V2 = P1 x V1 / P2
V2 = 42.0 x 12.5 / 75.0
V2 = 7.0 L
Answer:
7.00 L
Explanation:
The only thing that varies between the two situations is pressure and volume.
we have the ideal gas equation
We know that n = moles of substance remain constant, also the temperature and n corresponding to the ideal gas constant
Situation N1
Situation N2
As nrT are equal both times, therefore we can match this term in both equations
We equate both equations
(3) The volume of each atom decreases.
(4) The frequency of collisions between atoms increases.
Answer is: (4) The frequency of collisions between atoms increases.
The average kinetic energy of molecules depends on the temperature.
As temperature increases, molecules gain more energy from surrounding and move faster and have more collisions.
Kinetic energy (standard unit is the joule J) depends on speed of the molecule.
Charles' Law (The Temperature-Volume Law) - the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature:
V₁/T₁ = V₂/T₂.
When temperature goes up, the volume also goes up.
2. Calculate the moles of O in the sample.
Answer:
The answers are
C = 0.0895 moles
1. 0.02975 moles of N
2. 0.0299 moles O
Explanation:
Mass of sample = 2.18 g
Combustion yields 3.94 g of CO₂ and 1.89 g of H₂O
1.23 g of sample contains 0.235 g of N
3.94 g of CO₂ which contains one mole of C and two moles of O
Molar mass of CO₂ = 44 mass fraction of C = 12/44 = 0.273, Therefore mass of carbon in 2.18 g = 0.273×3.94 = 1.075 g
number of moles of C in sample = mass/(molar mass) = 1.075 g/(12.01 g/mol) = 0.0895 moles of C
(1) Mass of nitrogen, in 1.23 g of sample = 0.235
therefore mass in 2.18 g =0.235×2.18/1.23 = 0.4165 g
= 0.02975 moles of N
(2) To find the number of moles of oxygen in the sample we note that total mass of sample = 2.18 g containing only nitrogen, hydrogen, oxygen and carbon
Mass of hydrogen can be fround from 2/18×1.89 = 0.21 g
Mass of oxygen therefore = 2.18 -(0.21+0.4165+1.075) = 0.4785
number of moles = 0.475/16 = 0.0299 moles