**************************HOPING THAT THIS WILL HELP YOU!!!*******************************
21+(4x8)-2 would be nice to help me I need it soon!
Answers
Step-by-step explanation:
Using BODMAS
BRACKET (4×8)
21+32-2
53-2
•••
ANSWER== 51
A car leaves a town traveling at 60 miles per hour. Two hours later, a second car leaves the town traveling the same route and overtakes the first car in 6 hours and 40 minutes. How fast was the second car traveling?
Answers
After two hours, the first car has traveled (2 x 60) = 120 miles. That's the gap that the second car has to close.
The second car closes the gap of 120 miles in 6-2/3 hours. He must have exceeded the first car's speed by (120/6-2/3) mph.
6-2/3 = 20/3
120 divided by 20/3 = 120 x 3/20 = 360/20 = 18 mph
The second car exceeded the first car's speed by 18 mph, so he had to be traveling (60 + 18) = 78 mph to catch up.
Check:
In 6-2/3 hours . . .
The first car covers (60 x 20/3) = 400 miles.
The second car covers (78 x 20/3) = 520 miles. This is the same distance as the first car PLUS the 120 that he was behind when he started out. yay !
78 mph The second car travels 520 miles in 400 minutes. 520/400=1.3. 1.3*60=78.
If a+b+c=0 for a,b,c then prove a²/bc+b²/ca+c²/ab=3.
Answers
according to the identity if a+b+c=0 then a3+b3+c3=3abc a3+b3+c3/abc=3 a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3 cancel a,b,c in all the fraction then you get a²/bc+b²/ca+c²/ab=3. hence proved