Answer:
y-3 = 2/9 (x-8)
Step-by-step explanation:
b. Calculate the arithmetic mean. (Round your answer decimal places.)
c. Calculate the variance. (Round your answer to 2 decimal places.)
Answer:
a.) range- 6.2
b.) arithmetic mean- 13.85
c.) varience- 0.69
B. 9 cm
C. 8 cm
D. 6 cm
Answer:
Is letter D. X=6.
Step-by-step explanation:
3/4.5= 4/QR
18/3=6
Answer:I think it c
Step-by-step explanation:
Answer:
The correct answer is $800.
Step-by-step explanation:
Let the length and width of the field be equal to l meters and b meters respectively and l > b.
Area of the field is given by l × b = 400 square meters.
The river is supposed to be along the longest side so that the price of fencing the other three sides is minimum. Thus the total perimeter of the fence is b+ b+ l = 2b+l.
Total cost for fencing the other sides of the field = $ 10 × (2b + l)
The wall is supposed to be perpendicular to the river and thus the length of the wall is b meters.
Total cost for the wall is $ 20 × b
Therefore, the total price for making the field is given by
C = 10 × (2b + l) + 20 × b
⇒ C = 40b + 10l
⇒ C = + 10l
To minimize the cost we differentiate the cost with respect to l and equate it to zero.
= 0 = - + 10
⇒ = 1600
⇒ l = 40 ; [ negative sign neglected as length cannot be negative ]
⇒ b = 10
The second order derivative of C is positive giving the minimum value of the cost.
Thus the minimum cost required to make the field is given by $800.
To find the lowest possible cost to build the field, we need to determine the dimensions that will yield the minimum perimeter and then calculate the total cost of building the field. By differentiating the cost equation and solving for x, we can find the dimensions that minimize the cost.
To find the lowest possible cost to build the field, we need to determine the dimensions that will yield the minimum perimeter. Since the area of the field is 400 square meters and it will be divided into two equal halves by a brick wall, each half will have an area of 200 square meters. Let's say the length of the field is x meters. Then the width of each half will be 200/x meters.
The perimeter of the field is the sum of the lengths of the three sides:
Perimeter = 2x + 200/x + 200/x
Now, we can define the total cost to build the field as:
Total Cost = Cost of wall + Cost of fence
Cost of wall = 2x * $20 (since there are two halves)
Cost of fence = (2x + 200/x + 200/x) * $10 (since there is a fence on three sides)
Therefore, the total cost is: Total Cost = 2x * $20 + (2x + 200/x + 200/x) * $10.
To minimize the cost, we can differentiate the total cost with respect to x and set it equal to zero:
d(Total Cost)/dx = 0
Simplifying this equation will give us the value of x that minimizes the cost. We can solve this equation to find the minimum cost to build the field.
#SPJ3
Answer:
112 years ago
Step-by-step explanation:
38 => 14 yrs
DIfference: 24 yrs
n=8(14)
n=112
Therefore, 112 years ago
Answer:
Pr = 15.71% ≈ 16%
Step-by-step explanation:
Let's begin by listing out the data given unto us, we have:
Length of board = 3 ft, Width of board = 5 ft,
Area of board = Length * Width = 3 * 5 = 15 ft²,
Diameter of each circle (d) = 1 ft; r = d ÷ 2
⇒ r = 1 ÷ 2 = 0.5 ft
Area of each circle = πr² = π * 0.5² = 0.785 ft²
Area of the three circles = 3πr² = 2.356 ft²
Probability = favourable outcome ÷ Total outcome
Probability of the penny falling into the hole = area of the three circles ÷ area of board
Pr = 2.356 ÷ 15 = 0.1571
Converting to percentage, we multiply by 100
Pr = 0.1571 * 100
Pr = 15.71% ≈ 16%
Therefore, the probability of the penny falling into the hole is 15.71% ≈ 16%