Answer:
C/R = D
Step-by-step explanation:
When you divide rd by r, then r is eliminated and divided into the C
Answer:
So the width is 3.25
Step-by-step
If the perimeter of a rectangle is 300 and the length is two times the
width, what are the length and the width?
*Please don't get upset if this is incorrect, I am in 9th grade and I have severe dyslexia and dyscalculia*
:)
Given the length is 3 more than the width, and the perimeter is 26 inches, by solving the equation corresponding to the perimeter of the rectangle, we find that the width of the rectangle is 5 inches.
The question is asking for the width of a rectangle given that its length is 3 more than its width and the perimeter is 26 inches. Let's denote the width as x. Therefore, the length is x + 3.
The formula for the perimeter of a rectangle is 2*(length + width), which in this case translates into 2*(x + (x + 3)). As given, this equals 26. Solving the equation 2*(2x + 3) = 26, we find that x = 5. Therefore, the width of the rectangle is 5 inches.
#SPJ2
The length of the middle segment RS is determined as 18.
Let's assume that the three consecutive even integers are x, x + 2, and x + 4
So, the length of PR (x) + the length of RS (x + 2) + the length of SQ (x + 4) equals the total length of PQ (54).
Mathematically, this can be represented as:
x + (x + 2) + (x + 4) = 54
Now, let's solve for x:
3x + 6 = 54
Subtract 6 from both sides:
73x = 48
Now, divide by 3:
x = 16
So, the first even integer (PR) is 16, the second even integer (RS) is 16 + 2 = 18, and the third even integer (SQ) is 16 + 4 = 20.
Thus, the length of the middle segment RS is 18.
Learn more about middle segment here: brainly.com/question/26166058
#SPJ3
Answer:
RS = 18
Step-by-step
PR = x
RS = x+2
SQ = x+4
x+(x+2)+(x+4)=54
3x+6=54
3x=48
x=16
PR = 16
RS = 18
SQ = 20
f(x)=7x+15 g(x)=5x-6
=============================
Work Shown:
f(x) - g(x) = [ f(x) ] - [ g(x) ]
f(x) - g(x) = [ 7x+15 ] - [ 5x-6 ]
f(x) - g(x) = 7x+15 - 5x+6
f(x) - g(x) = (7x-5x)+(15+6)
f(x) - g(x) = 2x+21