The function C(x) = x 2 + 78 x + 29 models the cost, in hundreds of dollars, to produce x thousand pens. Find and interpret C(0), C(2) and C(4)

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

Given the function C(x) = x 2 + 78 x + 29 models the cost, in hundreds of dollars, to produce x thousand pens, we are to interpret C(0), C(2) and C(4).

For C(0), we are to substitute x = 0 into the given function;

C(0) = 0²+78(0)+29

C(0) = 0+0+29

C(0) = 29

Since the cost C(x) is in hundreds of dollars, C(0) = 2900

C(0) means that the cost of producing 0 thousand pen is $2,900

For C(2), we are to substitute x = 2 into the given function;

C(2) = 2²+78(2)+29

C(2) = 4+156+29

C(2) = 189

Since the cost C(x) is in hundreds of dollars, C(2) = 189*100 = $18900

C(2) means that the cost of producing 2 thousand pens is $18,900

For C(4), we are to substitute x = 4 into the given function;

C(4) = 4²+78(4)+29

C(4) = 16+312+29

C(4) = 357

Since the cost C(4) is in hundreds of dollars, C(4) = 357

C(4) means that the cost of producing 4 thousand pens is $35,700

Answer 2
Answer:

Final answer:

C(x) = x^2 + 78x + 29 models the cost to produce x thousand pens. Calculating C(0), C(2), and C(4), we find that C(0) = 29, C(2) = 189, and C(4) = 357. These values represent the cost in hundreds of dollars for producing 0, 2, and 4 thousand pens, respectively.

Explanation:

To find and interpret C(0), C(2), and C(4), we substitute the given values of x into the function C(x).

1.For C(0), we substitute 0 into the function C(x):

  1. C(0) = (0)^2 + 78(0) + 29
  2. C(0) = 0 + 0 + 29
  3. C(0) = 29
  4. So, C(0) = 29 hundred dollars, meaning it costs $2900 to produce 0 thousand pens.
  5. For C(2), we substitute 2 into the function C(x):
  6. C(2) = (2)^2 + 78(2) + 29
  7. C(2) = 4 + 156 + 29
  8. C(2) = 189
  9. So, C(2) = 189 hundred dollars, meaning it costs $18,900 to
  10. produce
  11. 2 thousand pens.
  12. For C(4), we substitute 4 into the function C(x):
  13. C(4) = (4)^2 + 78(4) + 29
  14. C(4) = 16 + 312 + 29
  15. C(4) = 357
  16. So, C(4) = 357 hundred dollars, meaning it costs $35,700 to produce 4 thousand pens.

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A company has a property tax bill for $6,000 this year. It expects property values to rise by 8% each year and therefore increase the property tax bill by 8% each year. What is the expected amount of property taxes the company will pay for this year and the upcoming three years? $24,080
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Answers

Year                     
1     6,000 x 1.08       =   6,480
2     6,480 x 1.08       =   6,998.40
3     6,998.40 x 1.08 =   7,558.27
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Answer:

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Step-by-step explanation:

The population of a pack of wolves is 88. The population is expected to grow at a rate of 2.5% each year.Which function equation represents the population of the pack of wolves after t years?

f(t)=88(0.025)^t

f(t)=88(1.025)^t

f(t)=88(1.25)^t

f(t)=88(2.5)^t

Answers

Answer:

Option B is correct.

f(t) = 88(1.025)^trepresents the population of the pack of wolves after t years

Step-by-step explanation:

The exponential growth function is given by;

f(t) = a(1+r)^t               ......[1]

where

a represented the initial value

r represents the rate(in decimal)

t represents the time in years

As per the given statement: The population of a pack of wolves is 88. Also, the population is expected to grow at a rate of 2.5% each year.

⇒ a = 88 and  r =2.5% = 0.025.

Substituting these values in equation [1], we have;

f(t) = 88(1+0.025)^t

or

f(t) = 88(1.025)^t

Therefore, the population model of the pack of wolves after t years is given by:  f(t) = 88(1.025)^t





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Answers

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Identity Property is a property that states that the sum of any number and zero is always the number you added to zero. This is also the case for multiplication by instead of adding zero, you are multiplying by one.

Hope this helps!


It is 2. Identity Property of Addition. The Identity Property of Zero, also called the Additive Identity Property, states that if you add 0 to any number, the result will be that number. ... Think about it: when you add or subtract zero from the number, it retains its identity...it doesn't change! It works for all real numbers (and on variables).