Answer:
Step-by-step explanation:
Given the function C(x) = x 2 + 78 x + 29 models the cost, in hundreds of dollars, to produce x thousand pens, we are to interpret C(0), C(2) and C(4).
For C(0), we are to substitute x = 0 into the given function;
C(0) = 0²+78(0)+29
C(0) = 0+0+29
C(0) = 29
Since the cost C(x) is in hundreds of dollars, C(0) = 2900
C(0) means that the cost of producing 0 thousand pen is $2,900
For C(2), we are to substitute x = 2 into the given function;
C(2) = 2²+78(2)+29
C(2) = 4+156+29
C(2) = 189
Since the cost C(x) is in hundreds of dollars, C(2) = 189*100 = $18900
C(2) means that the cost of producing 2 thousand pens is $18,900
For C(4), we are to substitute x = 4 into the given function;
C(4) = 4²+78(4)+29
C(4) = 16+312+29
C(4) = 357
Since the cost C(4) is in hundreds of dollars, C(4) = 357
C(4) means that the cost of producing 4 thousand pens is $35,700
C(x) = x^2 + 78x + 29 models the cost to produce x thousand pens. Calculating C(0), C(2), and C(4), we find that C(0) = 29, C(2) = 189, and C(4) = 357. These values represent the cost in hundreds of dollars for producing 0, 2, and 4 thousand pens, respectively.
To find and interpret C(0), C(2), and C(4), we substitute the given values of x into the function C(x).
1.For C(0), we substitute 0 into the function C(x):
#SPJ3
$24,480
$27,037
$29,200
Answer:
The answer on edge is C) 27,037
Step-by-step explanation:
f(t)=88(0.025)^t
f(t)=88(1.025)^t
f(t)=88(1.25)^t
f(t)=88(2.5)^t
Answer:
Option B is correct.
represents the population of the pack of wolves after t years
Step-by-step explanation:
The exponential growth function is given by;
......[1]
where
a represented the initial value
r represents the rate(in decimal)
t represents the time in years
As per the given statement: The population of a pack of wolves is 88. Also, the population is expected to grow at a rate of 2.5% each year.
⇒ a = 88 and r =2.5% = 0.025.
Substituting these values in equation [1], we have;
or
Therefore, the population model of the pack of wolves after t years is given by:
That is Identity Property of Addition.
Identity Property is a property that states that the sum of any number and zero is always the number you added to zero. This is also the case for multiplication by instead of adding zero, you are multiplying by one.
Hope this helps!
It is 2. Identity Property of Addition. The Identity Property of Zero, also called the Additive Identity Property, states that if you add 0 to any number, the result will be that number. ... Think about it: when you add or subtract zero from the number, it retains its identity...it doesn't change! It works for all real numbers (and on variables).