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Simplify 5/6i please help

Answers

Answer 1

Answer:

Answer:

5/6 can´t be simplified

Step-by-step explanation:

Answer 2

Answer:

Answer:

5i/6

Step-by-step explanation:

$(5)/(6)i\n\n\mathrm{Multiply\:fractions}:\quad \:a\cdot (b)/(c)=(a\:\cdot \:b)/(c)\n=(5i)/(6)$

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What is 4/5 + 2/5 =?
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Kevin plants a total of 72 flower in equal rows. He plants 6 rows of of yellow flowers and 2 rows of red flowers. How any flowers are in each row?

Answers

Answer: 36

Step-by-step explanation: 72/6= 36

72/2= 37

Hey can you please help me posted picture of question

Answers

Each leaf on the tree diagram represents a possible combination. So we are to find the total number of combinations for the given scenario.

There are 5 ways to select the pant, 7 ways to select a shirt and 3 ways to select the shoes.

Total number of combinations will be the product of all these ways the dress items can be selected.

So, number of combination of outfits = 5 x 7 x 3 = 105

Therefore, option B gives the correct answer

If bd = 7x - 10, BC= 4x - 29, and cd
= 5x - 9, find each value

Answers

Answer:

BD = 88

BC = 27

CD = 61

Explanation:

Given that,

BD = 7x - 10

BC= 4x - 29

CD = 5x - 9

Here we assume BD is a line segment and C is a point lies between B & D.

BD = BC + CD

7x - 10 = 4x - 29 + 5x - 9

Now combine like terms

7x - 10 = 4x + 5x - 29 - 9

7x - 10 = 9x - 38

Move 7x from left hand side to right hand side

-10 = 9x - 7x - 38

-10 = 2x - 38

Add 38 both the side

-10 + 38 = 2x - 38 + 38

28 = 2x

Divide by 2 both the side

x = 14

Now put the value of x and find the length of BD, CD, BC

BD = 7x - 10 = 7*14 - 10 = 98 - 10 = 88

BC= 4x - 29 = 4*14 - 29 = 56 - 29 = 27

CD = 5x - 9 = 5*14 - 9 = 61

That's the final answer.

I hope it will help you.

The value of the expression will be:

BD = 88

BC = 27

CD = 61

How to solve the expression

Given that,

BD = 7x - 10

BC= 4x - 29

CD = 5x - 9

Here we assume BD is a line segment and C is a point lies between B & D.

BD = BC + CD

7x - 10 = 4x - 29 + 5x - 9

Now combine like terms

7x - 10 = 4x + 5x - 29 - 9

7x - 10 = 9x - 38

Move 7x from left hand side to right hand side

-10 = 9x - 7x - 38

-10 = 2x - 38

Add 38 both the side

-10 + 38 = 2x - 38 + 38

28 = 2x

Divide by 2 both the side

x = 14

Now put the value of x and find the length of BD, CD, BC

BD = 7x - 10 = 7*14 - 10 = 98 - 10 = 88

BC= 4x - 29 = 4*14 - 29 = 56 - 29 = 27

CD = 5x - 9 = 5*14 - 9 = 61

Learn more about expressions

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Hey can you please help me posted picture of question

Answers

Horizontal translations
Suppose that h> 0
To graph y = f (x + h), move the graph of h units to the left.
We have then:
G (x) = f (x + h)
G (x) = (x + 5) ^ 2
Answer:
The graph of G (x) is given by:
G (x) = (x + 5) ^ 2
option D

From the graphs we can observe that G(x) is 5 units to the left of F(x).

This means a horizontal translation of 5 units to the left of F(x) will result in G(x). Such a translation can be obtained from adding 5 to each x in the equation.

So,

G(x) = F(x+5)

F(x) = (x+5)²

So the correct answer is option D

A trough has a semicircular cross section with a radius of 9 feet. Water starts flowing into the trough in such a way that the depth of the water is increasing at a rate of 2 inches per hour. (a) Give a function w = f(t) relating the width w of the surface of the water to the time t, in hours. Make sure to specify the domain and compute the range too.(b) After how many hours will the surface of the water have width of 6 feet?

(c) Give a function t = f −^1 (w) relating the time to the width of the surface of the water. Make sure to specify the domain and compute the range too.

Answers

Answer:

(a) Let h represents the height of water and w represents the width of the water,

Since, the depth of the water is increasing at a rate of 2 inches per hour,

So, after t hours,

The height of water, h(t) = 2t inches = t/6 ft,

( ∵ 1 foot = 12 inches ⇒ 1 inch = 1/12 ft )

Thus, the distance distance from the centre to the top of the water, d = 9 - h(t) ( see in the diagram )

$d=9-(t)/(6)$ ,

By the Pythagoras theorem,

$d^2 + ((w)/(2))^2 = 9^2$

$(9-(t)/(6))^2 +(w^2)/(4) = 81$

$(t^2)/(36)-(18t)/(6) + (w^2)/(4)=0$

$(t^2 - 108t + 9w^2)/(36)=0$

$t^2 - 108t + 9w^2 =0$

$9w^2 = 108t - t^2$

$w = (1)/(3)√(108t - t^2)$

Since, diameter of the semicircular cross section is 18 ft,

So, 0 ≤ w ≤ 18,

i.e Range = [0, 18]

Also, w will be defined if 108t - t² ≥ 0

⇒ (108 - t)t ≥ 0,

⇒ 0 ≤ t ≤ 108

i.e Domain = [0, 108]

(b) If w = 6,

$6 =(1)/(3)√(108t - t^2)$

$18 =√(108t-t^2)$

$324 = 108t - t^2$

$\implies t^2 - 108t+ 324=0$

By using quadratic formula,

$\implies t = 3.088\text{ or }t = 104.912$

Hence, After 3.1 hours or 104.9 hours will the surface of the water have width of 6 feet.

(c) $w = (1)/(3)√(108t- t^2)$

$\implies 3w = √(108t- t^2)$

$9w^2 = 108t - t^2$

$-9w^2 = -108t + t^2$

$-9w^2 + 2916 = 2916 - 108t + t^2$

$2916 - 9w^2 = (t - 108)^2$

$(t-108) = √(2916 - 9w^2)$

$t = √(2916 - 9w^2) + 108$

For 0 ≤ w ≤ 18,

0 ≤ t ≤ 108,

So, Domain = [0, 18]

Range = [0, 108]

Final answer:

The width of the water's surface in a semicircular trough can be represented by the function w=t/3 and its domain is t ≥ 0 and the range is 0 ≤ w ≤ 6. To have a 6 feet wide surface, thus, it would take 18 hours. The inverse function is t=3w, with a domain of 0 ≤ w ≤ 6 and range of t ≥ 0.

Explanation:

Given that the depth of the water is increasing at a rate of 2 inches per hour in a semicircular trough, we can convert this rate to feet per hour by dividing by 12, getting an increase of 1/6 feet per hour.

(a) We can express the width of the surface of the water as a function of time. We consider the cross-section of the trough is a semicircle. So, the radius of the water's surface will be the height of water, and this height increases at 1/6 feet per hour. Therefore, the width of the surface of water, w=2r=2*1/6t=t/3. The domain of the function is t ≥ 0 and the range is 0 ≤ w ≤ 6.

(b) We set w=6 in the function w=t/3 and solve for t. We get t=3*6=18 hours.

(c) The inverse function of w=t/3 is t=3w. The domain of the inverse function is 0 ≤ w ≤ 6 and the range is t ≥ 0.

Learn more about Mathematical functions here:

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Will Mark Brainlest help please

Answers

Answer:

g(-1 )=-1 and g(2)+g(1)=7

Step-by-step explanation:

If g(x) = x^3+x^2-x-2 find g(-1)

if we find g(-1)

we substitute all the x's in the function with -1

-1^3+-1^2-(-1)-2

-1^3 = -1

-1^2 = 1

-1+1+1-2

(two minuses make a plus)

-1+1 = 0

0+1 = 1

1-2 = -1

if x=-1, g(-1) is -1

g(2)+g(1)

substitute the x's in the function with 2 and 1 and add your results

2^3+2^2-2-2

2^3 = 8, 2^2 = 4

8+4-2-2

8+4= 12, 12-2 = 10, 10-2 = 8

g(2)=8

g(1) now

1^3 + 1^2-1-2

1^3=1, 1^2 = 1

1+1-1-2

1+1 = 2, 2-1 = 1, 1-2 = -1

g(3) = -1

g(2) (which equals 8) + g(3) (which equals -1) =

8+(-1) = 7

g(2)+g(3)=7

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