Answer:
Step-by-step explanation:
we have
Let
Exchange variables x for y and y for x
Isolate the variable y
Let
-------> inverse function
a. x – 8 = 2(y – 6)
b. y – 8 = 2(x – 6)
c. y + 8 = –2(x – 6)
d. y – 8 = –2(x – 6)
x = –6 or x = –8
x = 6 or x = –8
x = 6 or x = 8
x2 = 160
The value f(5) when f)1) = 3 is f(5) = 43.
The fifth term of the sequence can be found by finding the value of all the terms that precede it.
The value of f(1) is given as:
f(1) = 3
With this, we can find the value of f(2) and with f(2), we can find the value of f(3), and so on.
f(n) = - 2f(n-1)+1
At n = 2:
f(2) = -2f(2-1)+1
= - 2f(1)+1
= - 2*3 + 1
= - 5
When n = 3:
f(3) = -2*-5 + 1
= 11
When n = 4:
f(4) = -2*11 + 1
= -21
When n = 5:
f(5) = -2*-21 + 1
= 43
Therefore, we have found the value of f(5) to be f(5) = 43.
Learn more about sequences here: brainly.com/question/6561461
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