Set G is the set of positive integers divisible by 4 and Set F is the set of perfectsquares. List the first 5 elements of set H, which contains numbers in G that are
also elements of F.

Greetings from Brasil...

G = {4; 8; 12; 16; 20; 24; 28; 32; 36; 40; 44; 48; 52; 56; 60; 64; 68; 72; 76; 80; 84; 88; 92; 96; 100; 104; ...}

F = {1; 4; 9; 16; 25; 36; 49; 64; 81; 100; ...}

So, according to the statement, it is desired:

G ∩ F - the intersection between the 2 sets, that is, which numbers are present simultaneously in the 2 sets....

Looking at the sets we conclude that

G ∩ F = {4; 16; 36; 64; 100}

OBS: note that in truth G are the multiples of 4

Final answer:

The first five elements of set H, which include positive integers divisible by 4 that are also perfect squares, are 4, 16, 36, 64, and 100.

Explanation:

The two sets mentioned in the problem are Set G, which contains positive integers divisible by 4, and Set F, which contains perfect squares. The intersection of these two sets is Set H. To find the elements of Set H, we look for numbers that are both divisible by 4 and perfect squares. The first five such numbers are 4, 16, 36, 64, and 100. For example, 16 is both a multiple of 4 and a perfect square because it can be expressed as 4*4 and is the square of 4. Similarly, 36 fits both criteria because it can be expressed as 4*9 and is the square of 6. We continue this pattern to identify the first five elements of Set H.

Learn more about Intersection of Sets here:

brainly.com/question/33193647

#SPJ2