Answer:
2.90
Explanation:
Any buffer system can be described with the reaction:
Where is the acid and is the base. Additionally, the calculation of the pH of any buffer system can be made with the Henderson-Hasselbach equation:
With all this in mind, we can write the reaction for our buffer system:
In this case, the acid is with a concentration of 0.413 M and the base is with a concentration of 0.237 M. We can calculate the pKa value if we do the "-Log Ka", so:
Now, we can plug the values into the Henderson-Hasselbach
The pH value would be 2.90
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Answer:
Explanation:
1 molecule contains 1 carbon atom.
9.837 * 10^24 molecules contains 9.837 * 10^24 atom of carbon.
It's a 1 to 1 ratio.
Explanation:
Hydrogen + Oxygen --> Water
(1) Write the balanced chemical equation describing this reaction using the lowest whole number coefficients.
2H2(g) + O2(g) ---> 2H2O(g)
(2) Identify the oxidizing agent and reducing agent.
Oxidizing agent = O (There is decrease in oxidation number from 0 to -2)
Reducing agent = H (There is increase in oxidation number form 0 to +1)
(3) Determine the number of electrons transferred in the balanced chemical equation
2H2(g) --> 4H+ + 4e- (4 hydrogen atom lost a single electron each)
O2 + 4e- --> 2O2- (Two oxygen gain 2 electrons each)
Total number of electrons transferred in the balanced chemical equation is 4.
The intermolecular forces that act between chlorine monofluoride (ClF) and hydrogen bromide (HBr) are dipole-dipole interactions. These types of forces result from the attraction between polar molecules.
The intermolecular forces that act between a chlorine monofluoride (ClF) molecule and a hydrogen bromide (HBr) molecule are
dipole-dipole interactions
. A
dipole-dipole interaction
is a type of force that results from the attraction between polar molecules. Since ClF and HBr are both polar molecules, they exhibit this kind of interaction. For instance, the positive end of the polar ClF molecule would be attracted to the negative end of the polar HBr molecule, and vice versa, leading to a
dipole-dipole interaction
.
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Between chlorine monofluoride and hydrogen bromide, the intermolecular forces present are dipole-dipole forces and London dispersion forces due to their polar nature and instantaneous polarizations of electron clouds respectively.
The intermolecular forces that act between a chlorine monofluoride molecule and a hydrogen bromide molecule are primarily the dipole-dipole forces. Dipole-dipole forces are attractive forces that occur between the positive end of one polar molecule and the negative end of another polar molecule. Both chlorine monofluoride and hydrogen bromide are polar molecules, and as such, they interact through dipole-dipole forces. Apart from this, there exists London dispersion forces which are weak forces resulting from instantaneous polarizations of electron clouds in molecules. Hence, between chlorine monofluoride and hydrogen bromide, both dipole-dipole forces and London dispersion forces act.
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Answer: The value of change in internal energy of the system is, 40 J.
Explanation : Given,
Heat absorb from the surroundings = 12 J
Work done on the system = 28 J
First law of thermodynamic : It is a law of conservation of energy in which the total mass and the energy of an isolated system remains constant.
As per first law of thermodynamic,
where,
= internal energy = ?
q = heat absorb from the surroundings
w = work done on the system
Now put all the given values in this formula, we get the change in internal energy of the system.
Therefore, the value of change in internal energy of the system is, 40J.