PLZZ ANSWER ASAP PLZZZ HELP MEEE

300

1:1

1*300:1*300

300:300

Whenever the two numbers in a ratio are the same it means that they're equal. Hope this helps :)

1. Use properties of logarithms with the given approximations to evaluate the expression. Use log2=0.693 and/or log6=1.792 to find log12.

Answer: log12 = log6 + log2 = 1.792 + 0.693 = 2.485.

2. Complete parts (a) and (b).

a. Write the inverse of y=8x in logarithmic form.

Answer: log8(y) = x.

b. Graph y=8x and its inverse and discuss the symmetry of their graphs.

Answer: The graph of y=8x and its inverse will have the same shape, but it will be flipped across the line y = x. This is known as the symmetry of their graphs.

3. 2log215 EVALUATE Use properties of logarithms with the given approximations to evaluate the expression. log3≈0.477 and log5≈0.699. Use one or both of these values to evaluate log27. Write as a single logarithm. Assume that variables represent positive numbers. 5log2x+2log2z

Answer: log27 = log5 + log3 = 0.477 + 0.699 = 1.176.

4. On the basis of data for the years 1918 through 1997, the expected life span of people in a country can be described by the function f(x) = 12.576ln x + 17.088 years, where x is the number of years from 1905 to the person's birth year. What does this model estimate the life span to be for people born in 1941?

Answer: This model estimates that the life span for people born in 1941 is 70.698 years.

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Answer:

Option: A(0.585)

Step-by-step explanation:

After arranging our data in ascending order we get that:

5.16   5.16   5.25   5.33   5.33   5.5   5.66   5.66   5.75   5.75   6   6   6.25

Quartiles divide a rank-ordered data set into four equal parts. The values that divide each part are called the first, second, and third quartiles; and they are denoted by Q1, Q2, and Q3, respectively.

• is the "middle" value in the first half of the rank-ordered data set.

• is the median value in the set.

• is the "middle" value in the second half of the rank-ordered data set.

The interquartile range is equal to Q3-Q1.

So, the Median()of data is given by: 5.66

also the lower half is:

5.16   5.16   5.25   5.33   5.33   5.5

Hence, the middle value or median of this lower half of this data lie between 5.25 and 5.33 which is 5.29.

Hence, =5.29

Similarly the upper half is:

5.66   5.75   5.75   6   6   6.25

Hence, the middle value or median of this upper half of this data lie between 5.75 and 6 which is 5.875

Hence, =5.875

Hence, the interquartile range=

Hence, option A is correct.

Answer: Option: A(0.585)

Step-by-step explanation:

The solution is: x-3y=6 in slope intercept form is y = x/3 -2.

Here, we have,

given that,

x-3y=6

Slope intercept form is y = mx+b

where m is the slope and b is the y intercept.

we have,

x-3y=6

Subtract x from both sides            

x-3y -x =6 -x

Combine

-3y = 6 -x

Divide all parts of the equation by 3              

-3y/3 = 6/3 -x/3

-y = 2 - x/3

or, y = x/3 -2

where,

Slope = 1/3

y intercept = -2

Hence, The solution is: x-3y=6 in slope intercept form is y = x/3 -2.

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