MATHEMATICS HIGH SCHOOL

A new backpack at the local store is originally priced $160. It is on sale for 35% off. What is the new sale price?

Answers

Answer 1

Answer:

Answer:

$104

Step-by-step explanation:

10% = 160 ÷ 10 = $16

5% = $16 ÷ 2 = $8

30 % = 16 x 3 = $48

48 + 8 = $56

$160 - $56 = $104

Hope this helps!

Related Questions

PLSSSS HELP IF YOU TRULY KNOW THISSS
A field goal kicker has a 90% success rate for field goals less than 40 yards. What is the probability that the kicker makes the next four out of four field goal attempts under 40 yards?Round the percentage to the nearest whole number.
(write the slope-intercept form of the equation of each line) helllpppppp- pls-
Subtract 5x+2x-11 from 3x+^2+8x-7
-6x+11 = 7-10x show all work

A figure is part blue and part red.it is 5/8 red what part of the figure is blue

Answers

If $(5)/(8)$ is red, than the remaining $(3)/(8)$ would be blue. $(5)/(8)$ + $(3)/(8)$ would give you $(8)/(8)$ .

State if the three sies lengths form a right triangle ; 10 cm , 49.5 cm , 50.5 cm

Answers

Well, 10<49.5+50.5, 49.5<10+50.5 and 50.5<10+49.5
Because these conditions are obeyed, you have a triangle.
A right triangle requires that $50.5^2=10^2+49.5^2 \n 2550.25=100+2450.25$
which is true. So, the triangle has a right angle.

Please answer ASAP! Your answer MUST include an explanation in order to receive points and the Brainliest answer. Thank you.

Answers

63 because if you look at the pattern each number is multiplied by seven so if you multiply the input which is nine by seven you would get 63.

in an ordinary day with no discount if u see the parretn you can get the cost per ticket by dividing the cost by number of tickets
1st : 21/3 =7
2nd: 35/5=7
3rd: 56/8 = 7
so the ticket in an ordinary day = $7
in friday they make discount by $2 so the new value of the ticket = the old value -2
so the ticket on friday = $5
so if you want 9 tickets
9*5 = $45

What is the difference of the polynomials? (8r6s3 – 9r5s4 3r4s5) – (2r4s5 – 5r3s6 – 4r5s4)

Answers

To answer the question above, distribute the negative sign to the subtrahend and combine like terms.
8r6s3 - 9r5s4 + 3r4s5 - 2r4s5 + 5r3s6 + 4r5s4
Combining like terms
8r6s3 + (-9r5s4 + 4r5s4) + (3r4s5 - 2r4s5) + 5r3s6

Simplifying the expressions will give an answer of,

8r6s3 - 5r5s4 + r4s5 + 5r3s6

The difference of the polynomials $(8r^6s^3 - 9r^5s^4 + 3r^4s^5) - (2r^4s^5 - 5r^3s^6 - 4r^5s^4)$ is $8r^6s^3 - 5r^5s^4 + r^4s^5 + 5r^3s^6$

How to determine the difference?

The expression is given as:

$(8r^6s^3 - 9r^5s^4 + 3r^4s^5) - (2r^4s^5 - 5r^3s^6 - 4r^5s^4)$

Open the bracket

$8r^6s^3 - 9r^5s^4 + 3r^4s^5 - 2r^4s^5 + 5r^3s^6 + 4r^5s^4$

Collect like terms

$8r^6s^3 - 9r^5s^4 + 4r^5s^4 + 3r^4s^5 - 2r^4s^5 + 5r^3s^6$

Evaluate the like terms

$8r^6s^3 - 5r^5s^4 + r^4s^5 + 5r^3s^6$

Hence, the difference of the polynomials $(8r^6s^3 - 9r^5s^4 + 3r^4s^5) - (2r^4s^5 - 5r^3s^6 - 4r^5s^4)$ is $8r^6s^3 - 5r^5s^4 + r^4s^5 + 5r^3s^6$

Answers

When you flip a fair coin, there is always a 50% chance of heads, and a 50% chance of tails. Not sure the rest of info is relevant here

Final answer:

Simulated coin tossing uses random numbers, where 0-4 and 5-9 represent heads and tails respectively. The theoretical probability of getting tails is 0.5, but empirical probabilities can differ. This discrepancy, assumed to reduce with more trials, is accounted for by the Law of Large Numbers.

Explanation:

In the context of the provided problem, you are attempting to simulate tossing a coin 20 times using a system of random numbers, where you've assigned 0-4 to represent heads and 5-9 to represent tails. Theoretically, in a fair coin toss, there's a 50% chance (0.5 probability) of getting either heads or tails.

However, experimental or empirical probability may not always align with this theoretical likelihood, especially in smaller samples. This discrepancy is due to randomness and doesn't necessarily imply the coin or system is biased. Over many trials, the relative frequency of getting tails should approach the theoretical probability, according to the law of large numbers.

To calculate the empirical probability of getting tails in your simulation, you would tally up the total number of 'tails' results (numbers 5-9) from your 20 trials, then divide that count by the total number of trials (20). So, if you get 12 'tails' results, your empirical probability would be 12/20 = 0.6.

Learn more about probability here:

brainly.com/question/32117953

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mike is taking a his social studies test . mike was only able to finish 1/6 of the test in 1/2 hour. how long will it take him to finish the test?

Answers

$1-(1)/(6)=(5)/(6)\n\n\begin{array}{ccc}(1)/(6)\ of\ the\ test&-&(1)/(2)\ h\n\n(5)/(6)\ of\ the\ test&-&x\ h\end{array}\ \ \ \ |cross\ multiply\n\n\n(1)/(6)x=(1)/(2)\cdot(5)/(6)\n\n(1)/(6)x=(5)/(12)\ \ \ \ \ |multiply\ both\ sides\ by\ 6\n\n\boxed{x=(5)/(2)=2.5\ (h)}\leftarrow time\ he\ will\ have\ to\ do\ the\ test\n\n\ntotal\ test\ time:2.5\ h+0.5\ h=3\ h$

1/2*6 = 3. It will take him 3 hours to finish his test if he continues on the same rate

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