Answer:
The entire class is done in 80 minutes
Step-by-step explanation:
20 % = 20/100 = 1/5
1/5 of the class in 16 minutes
Multiply each by 5
1/5 *5 of the class in 16*5 minutes
1 of the class in 80 minutes
The entire class is done in 80 minutes
AB = GI
BC = HI
DE = HI
m∠B = m∠D = m∠I
Which triangles must be congruent?
ΔABC and ΔDEF only
ΔGHI and ΔABC only
none of the triangles
ΔABC, ΔDEF, and ΔGHI
Answer: ΔABC, ΔDEF, and ΔGHI
Step-by-step explanation:
Given: In ΔABC, ΔDEF, and ΔGHI:
AB = DF AB = GI
BC = HI DE = HI
m∠B = m∠D = m∠I
In ΔABC and ΔGHI
AB = GI [given]
BC = HI [given]
m∠B = m∠I [given]
[ here m∠B and m∠I are the included angle of ΔABC and ΔGHI]
∴ ΔABC ≅ ΔGHI [by SAS congruence postulate]
In ΔABC and ΔDEF
AB = DF [given]
BC = DE [ Since BC = HI and DE = HI so by transitive property BC = DE]
m∠B = m∠D [given]
[ here m∠B and m∠D are the included angle of ΔABC and ΔDEF]
∴ ΔABC ≅ ΔDEF [by SAS congruence postulate]
Now, since ΔABC ≅ ΔGHI and ΔABC ≅ ΔDEF
⇒ ΔGHI ≅ ΔDEF [transitive property]
Hence, all the given triangles ΔABC, ΔDEF, and ΔGHI are con gruent to each other.
B) 14 feet
C) 28 feet
D) 40 feet
128
256
512
1024
Answer:
30*x + 14850/x
Step-by-step explanation:
Let x be the length of the two opposite sides of the region with material costs of $15 per linear foot.
Let y be the length of the other two sides
Now, we have the following equations
Area of the rectangular región = x * y = 450 ft2
Total cost of fencing = 15*x + 15*x + 15 *y + 18*y
Total cost of fencing = 30*x + 33 *y
We now that area is equal to 450 ft2 = x*y
So y = 450/x
Now we can substitute y in equation for Total cost of fencing and obtain a function that expresses the cost of fencing the region in terms of the length, x
Total cost of fencing = 30*x + 33 *(450/x)
Total cost of fencing = 30*x + 14850/x