The Quotient of two Rational Numbers is a Rational Number if and only if Numerator and Denominator are Multiples.
From Algebra, we know that a Rational Number is a Real Number of the form:
, , (1)
Where:
The Quotient can be an Integer or not. In the first case, all Quotients have their equivalent Rational Numbers.
Now, if we divide a Rational Number by another Rational Number, then we have the following expression:
If is a Rational Number, then it must also an Integer and if is an Integer, then and must be Multiples of each other.
The Quotient of two Rational Numbers is a Rational Number if and only if Numerator and Denominator are Multiples.
Please see this question related to Rational Numbers: brainly.com/question/24398433
Answer:
Yes,
Step-by-step explananation
The quotient of two rational numbers is always rational, and the reason for this lies in the fact that the product of two integers is always an rational number.
Answer:
80:280
Step-by-step explanation:
To share £360 in the ratio 2:7, you first find the value of one part by dividing £360 by the total number of ratio parts (9). Then, multiply each part of the ratio by this amount, resulting in £80 and £280.
To share £360 in the ratio 2:7, you first need to understand that the sum of the parts of the ratio (2+7) equals to 9 parts. The amount of £360 should be distributed into these 9 parts.
First, you divide the total amount by the total number of parts:
£360 / 9 = £40.
This result £40 is the value of 1 part. To find the amounts for the ratio 2:7, you multiply each part of the ratio by the value of 1 part:
#SPJ3
Answer:
123
Step-by-step explanation:
012+121
A. 2√3
OB. -12i
OC. -2√3
D. 2√31
E. 12/
The expression √√-12 is equivalent to -2√3.
The expression √√-12 represents the square root of the square root of -12. Since the square root of -12 is not a real number, the expression is not defined in the set of real numbers. However, it is possible to define the square root of a negative number using imaginary numbers. The choice equivalent to √√-12 is -2√3 or option C.
x + x + 6 - 7 + x
2x+2+x
3- X + 2x - 4 + 2x
X-1
X+1
Answer:
a and c
Step-by-step explanation:
Answer:
A- x + x + 6 – 7 + x
C- 3 – x + 2x – 4 + 2x
Step-by-step explanation:
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