Answer:
B, 10+ /10 units
Step-by-step explanation:
Answer:
72500
73205
72968
72758
73261
Answer:
Step-by-step explanation:
$0.45
$1.55
$2.05
- I am an odd number
- the sum of my digits is 6
- my ones is one more than my tens digit
- my hundreds digit is 5 times my one digit
what number am I?
2.
- all my digits are different
-my ones digit is 4 times my hundreds digit
- my thousands digit is a perfect square
-my ones digit is 3 more than my tens digit
what number am I?
Answer:
1. 501
2. 1258 or 4258 or 9258
Step-by-step explanation:
1. represent number (d3d2d1) in terms of x. let x = 10's digit (dxd) then
d2 = x
d1 = x + 1
d3 = 5(x + 1) = 5x + 5
d3 + d2 + d1 = 6
(5x + 5) + (x) + (x + 1) = 6
7x + 6 = 6
7x = 0
x = 0 SO
d3 = (5x + 5) = 5
d2 = 0
d1 = x + 1 = 1
501
2. d4d3d2d1 and d1 not = d2 not = d3 not = d4, let d3 = x and d2 = y then
d2 = y
d3 = x
d1 = 4x and d1 = y + 3 so 4x = y + 3 or y = 4x - 3
d4 = perfect square (1 or 4 or 9)
any d must be <= 9
d4d3d2d1 = (1 or 4 or 9)(x)(4x - 3))(4x) so x<3 (0,1,2) or d1 fails <= 9
(1,4,9)(0,1,2)((4x - 3 = (1,5))((4x = 0,4,8)
d3 (0,1,2) must be 2 because 0 does not work for d2 and 1 does not work for d1, so this make d1 (4x) = 8 so
(d4)(2)(4x - 3 = 5)(4x = 8) = d4 (1,4,9) and 258 so
1258 or 4258 or 9258